Answer:
the mass is m ' a so yes a and m
Explanation: first off ' m
Answer:
the change in internal energy of the gases is -3.0924 KJ
Explanation:
The computation of the change in internal energy of the gases is as follows;
Given that
Q = -3.1 KJ
= -3100 J
It is negative as the heat is lost from the mixture
And,
W = + 7.6 J
It is positive as the work is done in the mixture
Now we use the following equation
Delat E = Q + W
= -3100 J + 7.6 J
= -3092.4 J
= -3.0924 KJ
Hence, the change in internal energy of the gases is -3.0924 KJ
Given the equation N=O/P, solve for P by multiplying the left and right by P/N:
N * P/N = O/P * P/N
P = O/N
Answer:
A solution of acetic acid that is 60.0% HC₂H₃O₂ (by mass) indicates that it contains 60.0 g of acetic acid and 100.0 g of water.
Explanation:
A percentage is a way of expressing an amount as a fraction of 100. The mass percentage corresponds to physical units of the solutions and they allow to establish more precisely the concentration of the solutions and express them in terms of percentages.
Mass percentage indicates the amount in grams of solute per 100 grams of solution.
So a solution of acetic acid that is 60.0% HC₂H₃O₂ (by mass) indicates that it contains 60.0 g of acetic acid and 100.0 g of water.
Answer:
P2≈393.609Kpa so I think the answer is 394 kPa
Explanation:
PV=mRT Ideal Gas Law
m and R are constant because they dont change for the problem. That means
PV/T=mR = constant
so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.
So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)
P2 = 393609 Pa