If you have 8.56 g of H2, how many grams of NH3 can be produced?

1 answer:

4 0

N2 + 3H2 → 2 NH3 from bal. rxn., 2 moles of NH3 are formed per 3 moles of H2, 2:3 moleH2: 3.64 g/ 2 g/mole H2= 1.82 1.82 moles H2 x 2/3 x 17

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Explanation:

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$BOH(aq)\rightarrow OH^-+B^+$

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$HBr(aq)\rightarrow H^++Br^-$

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