The ionic equation will be:
<span>Mg2+(aq) + 2OH-(aq) + 2H+(aq) + 2NO3-(aq) → Mg2+(aq) + 2NO3-(aq) + 2H2O(l)
</span>And the net ionic:
<span>2OH-(aq) + 2H+(aq) → 2H2O(l)
</span>a Balanced equation would be:
<span>Mg(OH)2(aq) + 2HNO3(aq) → Mg(NO3)2 (aq) + 2H2O(l)
</span>Now thsi si so because of the standard equation which is base plus acid=Salt plus water. We need to have in mindo that Mg(OH)2 is sparingly soluble in water and is aqueous mos of the times
<span>A means of solving a problem or dealing with a difficult situation.
</span>
The products obtained from the dissociation of HNO₃ in water are hydronium ion, H₃O⁺ and nitrate ion, NO₃¯
An acid is a substance which when dissolved in water produces hydronium ion, H₃O⁺ as the only positive ion.
Strong acid ionize completely in water while weak acid only ionize to a certain degree (i.e partially) in water
Trioxonitrate (v) acid, HNO₃ is a strong acid and will ionize complete in water to form hydronium ion, H₃O⁺ and nitrate ion, NO₃¯ as illustrated below:
HNO₃ + H₂O —> H₃O⁺ + NO₃¯
Thus, the products for the dissociation equation are: hydronium ion, H₃O⁺ and nitrate ion, NO₃¯
Learn more: brainly.com/question/13173940
Answer:
Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
Explanation:
Moles of glucose = 
According to the reaction, 1 mol of gluocse gives 2 moles of ethanol.
Then 2.833 moles of glucose will give :
Mass of 5.667 moles of an ethanol :
5.667 mol × 46 g/mol = 260.682 g
Volume of ethanol = V
Density of the ethanol = 0.789 g/mL
Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
