Answer: 1.99 x 10²² molecules H2
Explanation:First we will solve for the moles of H2 using Ideal gas law PV= nRT then derive for moles ( n ).
At STP, pressure is equal to 1 atm and Temperature is 273 K.
Convert volume in mL to L:
750 mL x 1 L / 1000 mL
= 0.75 mL
n = PV/ RT
= 1 atm ( 0.75 L ) / 0.0821 L.atm/ mole.K ( 273 K)
= 3.3x10-² moles H2
Convert moles of H2 to atoms using Avogadro's Number.
3.3x10-² moles H2/ 6.022x10²³ atoms H2 / 1 mole H2
= 1.99x10²² atoms H2
The density of the metal object=6.0
Given:
Volume of the metal object=1.5ml
Mass of the metal object=9.0g
To find:
Density of the metal object
<u>Step by Step Explanation:
</u>
Solution:
According to the formula, Density of the metal object can be calculated as

Where, m=mass of the metal object
=density of the metal object
v=volume of the metal object
We know the values of v=1.5ml and m=9.0g
Substitute these values in the above equation we get

=9.0/1.5
=6.0
Result:
Thus the density of the metal object is 6.0
Answer: 0.123 M
Explanation:
According to the neutralization law:

where,
= molarity of
solution = ?
= volume of
solution = 15.00 ml
= molarity of
solution = 0.100 M
= volume of
solution = 18.44 ml
= valency of
= 1
= valency of
= 1


Therefore, the concentration of the unknown HBr solution is 0.123 M
Answer:
The correct answers are "They travel slower than P waves", "They result in much ground motion" and " They are produced by P and S waves".
Explanation:
A surface wave can travel through the existing interface between Earth and air, as well as between Earth and water. A clear example of this type of waves are Love and Rayleigh waves. They travel slower than primary waves, produce large movements in the ground and are produced by primary and secondary waves.
Have a nice day!
Answer:
electrons is the answer to your question