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3 years ago

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A standard backpack is approximately 30cm x 30cm x 40cm. Suppose you find a hoard of pure gold (density = 19.3 g/cm3) while trea

sure hunting in the wilderness. How much mass would your backpack hold if you filled it with the gold?

1 answer:

Law Incorporation [45]3 years ago

6 0

Answer:

30

Explanation:

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Maya is playing the guitar. She drums the strings and the guitar procedures noise. maya is transforming____energy into _____ener

posledela

The strumming is mechanical energy
the notes heard is sound energy
so use D

6 0

2 years ago

suppose that you are comparing several objects. is it correct to say that the object with the largest volume has the largest mas

Semmy [17]

Answer:

No

Explanation:

It is not correct to say that an object with the largest volume has the largest mass.

Mass and volume are not directly related. In fact, the relationship between them can be direct or inverse.

Mass is the amount of matter in a substance. Volume is the space a body occupies.

A balloon and a stone for example is a typical one.
A balloon has more volume but far lesser mass compared to a stone.
A stone, gravel sized has low volume but more massive than a balloon.

Therefore, it is wrong to say a balloon has more mass because it has more volume.

3 0

2 years ago

Use the ideal gas law to calculate the concentrations of nitrogen and oxygen present in air at a pressure of 1.0 atm and a tempe

notka56 [123]

Answer:

[N₂] = 0.032 M

[O₂] = 0.0086 M

Explanation:

Ideal Gas Law → P . V = n . R . T

We assume that the mixture of air occupies a volume of 1 L

78% N₂ → Mole fraction of N₂ = 0.78

21% O₂ → Mole fraction of O₂ = 0.21

1% another gases → Mole fraction of another gases = 0.01

In a mixture, the total pressure of the system refers to total moles of the mixture

1 atm . 1L = n . 0.082L.atm/mol.K . 298K

n = 1 L.atm / 0.082L.atm/mol.K . 298K → 0.0409 moles

We apply the mole fraction to determine the moles

N₂ moles / Total moles = 0.78 → 0.78 . 0.0409 mol = 0.032 moles N₂

O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂

4 0

3 years ago

Which of the following is the smallest volume?

jok3333 [9.3K]

The (B) answer (B) is (B) (B) (B)

6 0

3 years ago

The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibri

levacccp [35]

<u>Answer:</u> The equilibrium concentration of HCl is $2.26\times 10^{-3}M$

<u>Explanation:</u>

We are given:

Moles of $NH_4Cl(s)$ = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}$

Molarity of $NH_4Cl=\frac{0.564}{1}=0.564M$

The given chemical equation follows:

$NH_4Cl(s)\rightleftharpoons NH_3(g)+HCl(g)$

<u>Initial:</u> 0.564

<u>At eqllm:</u> 0.564-x x x

The expression of $K_c$ for above equation follows:

$K_c=[NH_3][HCl]$

The concentration of pure solid and pure liquid is taken as 1.

We are given:

$K_c=5.10\times 10^{-6}$

Putting values in above equation, we get:

$5.10\times 10^{-6}=x\times x\\\\x=2.26\times 10^{-3}M,-2.26\times 10^{-3}M$

Negative sign is neglected because concentration cannot be negative.

So, $[HCl]=2.26\times 10^{-3}M$

Hence, the equilibrium concentration of HCl is $2.26\times 10^{-3}M$

5 0

3 years ago