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2 years ago

In the metallurgic industry one of the processes to get pure iron takes tree steps.

Chemistry

1 answer:

Leni [432]2 years ago

6 0

Iron produced : 1.5 kg

<h3>Further explanation</h3>

Reaction

a) CaCO3→CaO + CO2

b) CO2 + C → 2CO

c) Fe2O3 + 3CO → 2Fe + 3CO2

mol CaCO₃ (MW=100,0869 g/mol) :

$\tt \dfrac{1340}{100,0869}=13.39$

mol CO₂ = mol CaCO₃ =13.39(reaction a)

mol CO = 2 x mol CO₂ = 26.78(reaction b)

mol CO(reaction c) = 1.5 mol CO from reaction b = 1.5 x 26.78 = 40.17

mol Fe(reaction c) = 2/3 x mol CO =

$\tt \dfrac{2}{3}\times 40.17=26.78$

Or we can cancel out the same compound in different sides from the sum of the three reactions to find mol Fe

a) CaCO3→CaO + CO2

b) CO2 + C → 2CO

c) Fe2O3 + 3CO → 2Fe + 3CO2

----------------------------------------------+

CaCO3 + Fe2O3 + C + CO + 3CO2 ⇒ CaO + 2Fe

mol Fe = 2 x mol CaCO3 = 2 x 13.39 = 26.78

mass Fe :

$\tt 26.78\times 55.845~g/mol=1495.53~g\approx 1.5~kg$

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The Law of Multiple Proportions states that ____.

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Answer: when two elements combine, A and B, the ratio of the weight of B combining with A is always a whole number

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Answer:

El volumen del cuerpo es el mismo al comienzo de la experiencia.

Explicación:

El volumen del cuerpo es el mismo al principio porque el volumen no cambia si la temperatura permanece igual. Si cambiamos la temperatura i. mi. Al aumentar la temperatura, las moléculas comienzan a expandirse y se produce un aumento de volumen mientras que cuando disminuimos la temperatura, las moléculas de esa sustancia comienzan a contraerse y el volumen de esa sustancia disminuye. Entonces concluimos que el volumen depende de la temperatura.

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3 years ago

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

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Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

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3 years ago

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Answer:

Explanation:

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3 years ago

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Answer:

Kindly check the explanation section.

Explanation:

PS: kindly check the attachment below for the required diagram that is the diagram showing solid sodium chloride looks like at the atomic level.

The chemical compound known as sodium chloride, NaCl has Molar mass: 58.44 g/mol, Melting point: 801 °C and

Boiling point: 1,465 °C. The structure of the solid sodium chloride is FACE CENTRED CUBIC STRUCTURE. Also, solid sodium chloride has a coordination number of 6: 6.

In the diagram below, the positive sign shows the sodium ion while the thick full stop sign represent the chlorine ion.

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