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AlekseyPX
2 years ago
8

In the metallurgic industry one of the processes to get pure iron takes tree steps.

Chemistry
1 answer:
Leni [432]2 years ago
6 0

Iron produced : 1.5 kg

<h3>Further explanation</h3>

Reaction

a) CaCO3→CaO + CO2

b) CO2 + C → 2CO

c) Fe2O3 + 3CO → 2Fe + 3CO2

mol CaCO₃ (MW=100,0869 g/mol) :

\tt \dfrac{1340}{100,0869}=13.39

mol CO₂ = mol CaCO₃ =13.39(reaction a)

mol CO = 2 x mol CO₂ = 26.78(reaction b)

mol CO(reaction c) = 1.5 mol CO from reaction b = 1.5 x 26.78 = 40.17

mol Fe(reaction c) = 2/3 x mol CO =

\tt \dfrac{2}{3}\times 40.17=26.78

Or we can cancel out the same compound in different sides from the sum of the three reactions to find mol Fe

a) CaCO3→CaO + CO2

b) CO2 + C → 2CO

c) Fe2O3 + 3CO → 2Fe + 3CO2

----------------------------------------------+

CaCO3 + Fe2O3 + C + CO + 3CO2 ⇒ CaO + 2Fe

mol Fe = 2 x mol CaCO3 = 2 x 13.39 = 26.78

mass Fe :

\tt 26.78\times 55.845~g/mol=1495.53~g\approx 1.5~kg

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A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?
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Answer:

80L

Explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

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2 years ago
A gas exerts a pressure of 350.0 torr at 20.0 Celsius. What would be the new pressure in atmospheres if the temperature is raise
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Answer:

373.88 torr

Explanation:

P1 = 350 torr

T1 = 20°C = (20 + 273.15)K = 293.15K

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From pressure law,

Pressure of a given mass of gas is directly proportional to its temperature.

P = KT

K = P / T

P1 / T1 = P2 / T2

Solve for P2

P2 = (P1 * T2) / T1

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5 0
3 years ago
Read 2 more answers
A 1.8 g sample of octane C8H18 was burned in a bomb calorimeter and the temperature of 100 g of water increased from 21.36 C to
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Answer:

HEAT OF COMBUSTION PER GRAM OF OCTANE IS 1723.08 J OR 1.72 KJ/G OF HEAT

HEAT OFF COMBUSTION PER MOLE OF OCTANE IS 196.4 KJ/ MOL OF HEAT

Explanation:

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

In other words, 3101.56 J of heat was evolved from the reaction of 1.8 g octane with water.

Heat of combustion of octane per gram:

1.8 g of octane produces 3101.56 J of heat

1 g of octane will produce ( 3101.56 * 1 / 1.8)

= 1723.08 J of heat

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1.8 g of octane = 3101.56 J

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