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3 years ago

Which element is located in period 3 of the periodic table?

Physics

1 answer:

liberstina [14]3 years ago

3 0

Answer:

From the given options, the option (D) is correct. Because Al is the aluminium which is located in period 3 of the periodic table.

Explanation:

We know that the 3rd period contains 8 elements which are as follows:

sodium
magnesium
aluminium
silicon
phosphorus
sulfur
chlorine, and
argon

The sodium and magnesium, the first 2 elements, are members of the s-block of the periodic table, while the rest of the members are the elements of the p-block.

Thus, from the given options, the option (D) is correct. Because Al is the aluminium which is located in period 3 of the periodic table.

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Which phase of matter is made up of particles that are packed relatively close together, with an indefinite shape but a definite

Bezzdna [24]

property of gas

gas molecules are very loosely bonded with each other so the force between the molecules is very weak

Due to this weak force the molecules of gas can attain any shape and any volume.

So gas moles have no finite shape and no finite volume

Property of Solids

Solids are tightly packed and having very strong bond between the molecules

If all molecules are tightly bonded then they have always a finite shape and finite volume so in this case we can not change the volume or shape of the solids as it is fixed.

Property of Liquids

Liquid molecules are moderately bonded together and since the force is more than the force between the gas molecules so liquids have finite volume but indefinite shape

liquid attains the shape of the container but its volume is fixed

So in above all examples Liquid is correct answer

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3 years ago

373698 on expanded num

Vladimir79 [104]

300,000+70,000+3,000+600+90+8

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3 years ago

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In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

Nat2105 [25]

Answer:

303

Explanation:

We are given that

Emf in coil 1, $E_1=3.13 V$

Emf induced in coil 2, $E_2=4.16 V$

Number of loops in coil 1, $N_1=228$

We have to find the number of loops in coil 2.

Rat of change of magnetic flux in a single loop is same.

Let $\phi_1$ and $\phi_2$ be the magnetic flux in coil 1 and coil 2.

$\frac{d\phi_1}{dt}=\frac{d\phi_2}{dt}$

$\frac{V_2}{V_1}=\frac{N_2}{N_1}$

Using the formula

$\frac{E_2}{E_1}=\frac{N_2}{N_1}$

$\frac{4.16}{3.13}=\frac{N_2}{228}$

$N_2=\frac{4.16}{3.13}\times 228$

$N_2=303$

Hence, the number of loops in coil 2=303

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3 years ago

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(15 POINTS) Victor drew a diagram to show the life cycle of a low-mass star.

Evgen [1.6K]

The answer is c so the area can grow

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