An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally througha distance of 6.00 m along a
frictionless surface. What is the change in the kinetic energy of thisobject?
2 answers:
Answer:
Δ K.E = 600 J
Explanation:
Given that:
the mass of the object = 10.0 kg
Force = 100 N
distance = 6.00 m
what is the change in kinetic energy of this object = Δ K.E
The expression for the change in the kinetic can be illustrated as follows:
Δ K.E = W
where W is the workdone on the object and is given by the formula :
W = F × d
So;
Δ K.E = F × d
Δ K.E = (100 N × 6.00 m)
Δ K.E = 600 N.m
Δ K.E = 600 J
Therefore, the change in the kinetic energy of this object = 600 J
Answer:
The change in the kinetic energy is 600 J
Explanation:
According the work energy expression, the change of kinetic energy is equal to the work done, the equation is:

Where
F = force = 100 N
s = distance = 6 m
Replacing:

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