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3 years ago

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An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally througha distance of 6.00 m along a

frictionless surface. What is the change in the kinetic energy of thisobject?

2 answers:

KonstantinChe [14]3 years ago

3 0

Answer:

Δ K.E = 600 J

Explanation:

Given that:

the mass of the object = 10.0 kg

Force = 100 N

distance = 6.00 m

what is the change in kinetic energy of this object = Δ K.E

The expression for the change in the kinetic can be illustrated as follows:

Δ K.E = W

where W is the workdone on the object and is given by the formula :

W = F × d

So;

Δ K.E = F × d

Δ K.E = (100 N × 6.00 m)

Δ K.E = 600 N.m

Δ K.E = 600 J

Therefore, the change in the kinetic energy of this object = 600 J

levacccp [35]3 years ago

3 0

Answer:

The change in the kinetic energy is 600 J

Explanation:

According the work energy expression, the change of kinetic energy is equal to the work done, the equation is:

$deltaE_{k} =W=Fs$

Where

F = force = 100 N

s = distance = 6 m

Replacing:

$deltaE_{k} =100*6=600J$

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Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t

NemiM [27]

Answer:

their final velocity is 0.091 m/s

Explanation:

Given;

mass of the first train, m₁ = 138,000 kg

mass of the second train, m₂ = 123,000 kg

initial velocity of the first train, u₁ = 0.288 m/s

initial velocity of the seocnd train, u₂ = -0.131 m/s (opposite direction to the first)

Let their common final velocity after been coupled = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(138,000 x 0.288) + (-0.131 x 123,000) = v(138,000 + 123,000)

39,744 - 16,113 = v(261,000)

23,631 = v(261,000)

v = 23,631 / 261,000

v = 0.091 m/s

Therefore, their final velocity is 0.091 m/s

5 0

2 years ago

A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. The student reports hearing two

katrin [286]

Answer:

a) L = 33.369 m , b) 21

Explanation:

The analysis of the ocean depth can be performed assuming that at the bottom of the ocean there is a node and the surface must have a belly, so the expression for resonance is

λ = 4 L / n

n = 1, 3, 5, ...

The speed of the wave is

v = λ f

v = 4L / n f

L = n v / 4f

Let's write the expression for the two frequencies

L = n₁ 343/4 53.95

L = n₁ 1,589

L = n₂ 343/4 59

L = n₂ 1.4539

Let's solve the two equations

n₁ 1,589 = n₂ 1,459

n₁ / n₂ = 1.4539 / 1.589

n₁ / n2 = 0.91498

Since the two frequencies are very close the whole numbers must be of consecutive resonances, let's test what values give this value

n₁ n₂ n₁ / n₂

1 3 0.3

3 5 0.6

5 7 0.7

7 9 0.77

9 11 0.8

17 19 0.89

19 21 0.905

21 23 0.913

23 25 0.92

Therefore the relation of the nodes is n₁ = 21 and n₂ = 23

Let's calculate

L = n₁ 1,589

L = 21 1,589

L = 33.369 m

b) the number of node and nodes is equal therefore there are 21 antinode

4 0

3 years ago

What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?

Setler [38]

Answer:

Momentum, $p=7.8\times 10^{-5}\ N-m$

Explanation:

Given that,

Mass of a mosquito, m = 0.000015 kg

Velocity of the mosquito, v = 5.2 m/s

We need to find the momentum of the mosquito. The momentum of an object is given by :

p = mv

Put all the values in the above formula.

$p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m$

So, the momentum of the mosquito is $7.8\times 10^{-5}\ N-m$ .

3 0

2 years ago

3 a A motorcyclist starts from rest and reaches

andrew-mc [135]

The acceleration of the body is 2 m/s^2 while the deceleration is - 1.2 m/s^2.

<h3>What is the acceleration?</h3>

Let us recall that the acceleration is the change in the speed of a body with time. We have been told that the body accelerates for 3s and then decelerates to 2s. This implies that the total time that the object spent in motion is 5 s.

Thus;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time taken

v - u/t = a

a = 6 - 0/3

= 2 m/s^2

Again;

v - u/t = a

a = 0 - 6/5

a = - 1.2m/s^2

Learn more about acceleration:brainly.com/question/12550364

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<h3 />

7 0

1 year ago

A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that th

olga nikolaevna [1]

Answer:

Approximately $7.8\; \rm J$ .

Explanation:

The change in the gravitational potential energy of the pendulum is directly related to the change in its height.

Refer to the sketch attached. The pendulum is initially at $\rm P_2$ . Its highest point is at $P_1$ . The length of segment $\rm BP_2$ gives the change in its height.

The lengths of $\rm AP_1$ and $\rm AP_2$ are simply the length of the string, $1.5\; \rm m$ . To find the length of $\rm BP_2$ , start by calculating the length of $\rm AB$ .

$\rm AB$ forms a leg in the right triangle $\rm \triangle AP_1B$ . Besides, it is adjacent to the $30^\circ$ angle $\rm P_1\hat{A}B$ . Its length would be:

$\rm AB = 1.5 \times \cos(30^\circ) \approx 1.30\; \rm m$ .

The length of $\rm BP_2$ would thus be

$\rm BP_2 = AP_2 - AB = 1.5 - 1.30 \approx 0.20\; \rm m$ .

The change in gravitational potential energy can be found with the equation

$\Delta \mathrm{GPE} = m \cdot g \cdot \Delta h$ . In this equation,

$m$ is the mass of the object,
$g \approx 9.81\; \rm N \cdot kg^{-1}$ near the surface of the earth, and
$\Delta h$ is the change in the object's height.

In this case, $m = 4\; \rm kg$ and $\Delta h \approx 0.20\; \rm m$ . Therefore:

$\Delta \mathrm{GPE} = 4 \times 9.81 \times 0.20 \approx 7.8\; \rm J$ .

6 0

3 years ago