Question

In the Millikan oil drop experiment the measured charge of any single droplet was always a whole number multiple of -1.60 x 10-19 C. If a single droplet was found to have a total charge of -9.60×10-19 C then how many excess electrons are contained within the drop?

Answer 1

Answer:

Number of electrons, n = 6

Explanation:

Total charge in a single droplet, $q=-9.6\times 10^{-19}\ C$

The measured charge of any single droplet, $e=-1.6\times 10^{-19}\ C$

Let n is the number of excess electrons are contained within the drop. According to the quantization of charge :

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{-9.6\times 10^{-19}}{-1.6\times 10^{-19}}$

n = 6

So, there are 6 electrons contained within the drop. Hence, this is the required solution.