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Dmitry [639]
3 years ago
11

Two vectors of magnitudes 30 units and 70 units are added to each other. What are possible results of this addition? (section 3.

3) 10 units 110 units 50 units 30 units
Physics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

50 units

Explanation:

Given,

  • magnitude of the first vector = a = 30 units
  • magnitude of the second vector = 70 units

As we know, From the law of vector addition,

Resultant of the addition of the two vectors is,

\therefor R\ =\ \sqrt{a^2\ +\ b^2\ +\ 2abcos\theta}

where \theta is the angle between the two vectors

And the value of cos\theat lies between -1 ≤ cos\theta ≥ 1.

For the possible values of the addition of the vectors

Therefore maximum possible value for the addition of the vector gives at the value of cos\theta\ =\ 1

\therefore R_{max}\ =\ \sqrt{30^2\ +\ 70^2\ + 2\times 30\times 70\times 1}\\\Rightarrow R_{max}\ =\ 100 units

Minimum possible value for the addition of the vectors gives at the value of cos\theta\ =\ -1

\therefore R_{min}\ =\ \sqrt{30^2\ +\ 70^2\ + 2\times 30\times 70\times (-1)}\\\Rightarrow R_{min}\ =\ 40 units

Hence the possible results of the addition of these two vectors is only 50 units which lies between the 40 units and 100 units.

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Answer:

-  path differnce = 2.18*10^-6

-  1538 lines

Explanation:

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path\ difference\ = dsin\theta           (1)

d: separation between slits = 0.50mm = 0.50*10^-3 m

θ: angle of a diffraction = 0.25°

Then, the path difference is:

path\ difference\ =(0.50*10^{-3}m)sin(0.25\°)=2.18*10^{-6}m

- The maximum number of bright lines are calculated by using the following formula:

m\lambda = dsin\theta           (2)

m: order of the bright

λ: wavelength = 650nm

The maximum bright is calculated for an angle of 90°:

m=\frac{(0.50*10^{-3}m)sin90\°}{650*10^{-9}m} \approx 769

The maxium number of bright lines are twice the previous result, that is, 1538 lines

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Answer:

a)  p = 4.96 10⁻¹⁹ kg m / s , b)  p = 35 .18 10⁻¹⁹  kg m / s ,

c)  p_correst / p_approximate = 7.09

Explanation:

a) The moment is defined in classical mechanics as

                 p = m v

Let's calculate its value

               p = 1.67 10⁻²⁷ 0.99 3. 10⁸

               p = 4.96 10⁻¹⁹ kg m / s

b) in special relativity the moment is defined as

               p = m v / √(1 –v² / c²)

Let's calculate

                p = 1.67 10⁻²⁷ 0.99 10⁸/ √(1- 0.99²)

                p = 4.96 10⁻¹⁹ / 0.141

                p = 35 .18 10⁻¹⁹  kg m / s

c) the relationship between the two values ​​is

            p_correst / p_approximate = 35.18 / 4.96

            p_correst / p_approximate = 7.09

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Answer:

The temperature change of the copper is greater than the temperature change of the water.

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The temperature change in the copper is nearly 11 times the temperature change in the water.

So, the correct option is,

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