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Dmitry [639]
3 years ago
11

Two vectors of magnitudes 30 units and 70 units are added to each other. What are possible results of this addition? (section 3.

3) 10 units 110 units 50 units 30 units
Physics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

50 units

Explanation:

Given,

  • magnitude of the first vector = a = 30 units
  • magnitude of the second vector = 70 units

As we know, From the law of vector addition,

Resultant of the addition of the two vectors is,

\therefor R\ =\ \sqrt{a^2\ +\ b^2\ +\ 2abcos\theta}

where \theta is the angle between the two vectors

And the value of cos\theat lies between -1 ≤ cos\theta ≥ 1.

For the possible values of the addition of the vectors

Therefore maximum possible value for the addition of the vector gives at the value of cos\theta\ =\ 1

\therefore R_{max}\ =\ \sqrt{30^2\ +\ 70^2\ + 2\times 30\times 70\times 1}\\\Rightarrow R_{max}\ =\ 100 units

Minimum possible value for the addition of the vectors gives at the value of cos\theta\ =\ -1

\therefore R_{min}\ =\ \sqrt{30^2\ +\ 70^2\ + 2\times 30\times 70\times (-1)}\\\Rightarrow R_{min}\ =\ 40 units

Hence the possible results of the addition of these two vectors is only 50 units which lies between the 40 units and 100 units.

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The will dog catch up with the rabbit in 6 minutes assuming both their velocities remain constant during the chase.

<h3>What time will the dog catch the rabbit?</h3>

The time that the dog will catch up with the rabbit is given as follows:

Let the distance covered by the rabbit be x.

Distance covered by dog = x + 30

  • Time taken = distance/speed

The time taken will be the same T

  1. Time taken by dog, T = (x + 30)/10
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Equating both times.

(x + 30)/10 = x/5

x = 30 m

Solving for T in equation (ii);

T = 30/5 = 6 minutes

In conclusion, time is obtained as a ratio of distance and speed.


Learn more about time and speed at: brainly.com/question/26046491

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A potent clear link between the luminosity and pulsation period of a Cepheid variable developed Cepheids as an important determinants of cosmic criteria for scaling galactic and extra galactic distances. Henrietta Swan Leavitt revealed this robust feature of conventional Cepheid in 1908 after observing thousands of variable stars in the Magellanic Clouds. This in fact turn, by making comparisons its established luminosity to its measured brightness, allows one to evaluate the distance to the star.

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135,000 kilometers = how many miles?
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How does wood and plastic relate to forces
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An 8.50 m long ladder leans against the side of a building. The ladder is initially inclined at an angle of 47.0° to the horizon
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The angle of the ladder inclined with respect to the horizontal after being moved a distance of 0.82 m closer to the building is 53.84°

cos θ = Adjacent side / Hypotenuse

θ_{1} = 47°

Hypotenuse = Length of ladder = 8.5 m

cos 47° = Adjacent side / 8.5

Adjacent side = Initial distance of base of ladder from the building = 5.8 m

Adjacent side 2 = Final distance of base of ladder from the building

Adjacent side 2 = 5.8 - 0.82 = 4.98 m

cos θ_{2} = Adjacent side 2 / Hypotenuse

cos θ_{2} = 4.98 / 8.5 = 0.59

θ_{2} = cos^{-1} ( 0.59 )

θ_{2} = 53.84°

The formula used above is one of trigonometric ratios. Trigonometric ratios can used only in a right angled triangle where one of the angles in at 90 degrees and the other two angles are less than 90 degrees.

Therefore, the angle of the ladder inclined with respect to the horizontal after being moved is 53.84°

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