1. V = IR
You rearrange it to make I the subject by dividing both sides by R. You get:
I = V / R
I = 10 / 50
= 0.2 A
2. Q = It
Charge = 0.2 x 2
Charge = 0.4 C
The correct answer for the question that is being presented above is this one: "c. radiation." The typical product of nuclear fission is radiation. Nuclear fission's another product is that<span> two different atoms that are both less massive than the original atom </span>
Answer:
The answer is Loading
Explanation:
The center of gravity is a point inside a mass where the weight of the mass is considered to act on. And the center of gravity of an object can change position if you add more mass on certain areas of the object. So lets say you have a vehicle and the vehicle has the center of gravity right in the middle (this means at mid-height, mid-length and mid-width). Now you put some stuff on the trunk, well guess what? The center of gravity now shifted some towards the trunk of your car. And if you didn´t place the extra mass right in the middle of the trunk, the you also moved the center of gravity to whatever side you put the mass on.
In regards of the other three options:
- Force of impact has nothing to do with center of gravity. Although if you want to be very strict, if you crash and the force of impact deforms your car so much that the vehicle has now a totally different shape, then yeah, all the rearrangement of the mass will move the center of gravity from its initial position. But for the scope of this question, the answer is NO.
- The antilock brakes or ABS have nothing to do with center of gravity. All they do is prevent your car from sliding by keepin the tires rotating when you slam on the brakes.
- Torque has nothing to do with center of gravity. More torque will help you with acceleration of your vehicle.
Answer: 45.1N
Explanation:
Answer: 45.1N
Explanation:
The work done in the block is equal to change in energy is the system. We then go ahead to calculate W with the given values of initial and final speed.
W= Ef - Ei
W= 1/2MVf² - 1/2MVi²
W= 1/2M (Vf² - Vi²)
W= 1/2 * 41 (6²-5²)
W= 1/2 * 41 * 11
W= 225.5J
We note the definition of work and solve for F.
Taking into cognizance the displacement we have been given in the question. We then have
F = W/x
F = 225.5/5
F = 45.1N
Answer:
I assume that the force of 2N is applied along the direction of motion and was applied for the whole 1 meter, the formula of work is this; Work = force * distance * cosθ where θ is zero degrees. Plugging in the data to the formula;
Explanation:
Work = 2N * 1m * cos 0º.
Work = 2N * 1m * 1
Work = 2Nm
Work = 2 joules