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Pavel [41]
3 years ago
5

Which best describes an element

Chemistry
1 answer:
-Dominant- [34]3 years ago
8 0

Answer:

a pure substance

Explanation:

cant be broken down into any more  simpler substances

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What are some shared properties of both transition metals and alkali metals.
RideAnS [48]

Both transition metals and alkali metals are good conductors of heat and electricity, react with water, and are easily oxidized.

<h3>What are alkali metals and transition metals?</h3>

The alkali metals are elements of group 1 which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr).  They are also known as the s-block elements because they have their outermost electron in an s-orbital.

The alkali metals are shiny, soft, highly reactive metals and readily lose their outermost electron to create cations with charge +1. They can tarnish rapidly in the air due to oxidation by atmospheric moisture and oxygen.

Transition elements or transition metals are elements that have partially filled d-orbitals. An element having a d-subshell that is partially filled with electrons or can form stable cations with an incompletely filled d orbital.

Any element present in the d-block of the modern periodic table which consists of groups 3 to 12, is considered to be a transition element. For example, the mercury in the +2 oxidation state, corresponds to an electronic configuration of (n-1)d¹⁰. Many paramagnetic compounds are formed by transition metals because they have unpaired electrons in the d orbital.

Learn more about transition metals and alkali metals, here:

brainly.com/question/15775417

#SPJ1

7 0
1 year ago
Help asap please help no links
sertanlavr [38]

Answer:

Food or Sun

Explanation:

I'm not sure if it's food or sun, but try both

5 0
3 years ago
Read 2 more answers
Combustion analysis of 0.600 g of an unknown compound containing carbon, hydrogen, and oxygen produced 1.043 g of CO2 and 0.5670
Aliun [14]

Answer : The empirical formula of the compound is C_3H_8O_2

Explanation :

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=1.043g

Mass of H_2O=0.5670g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 1.043 g of carbon dioxide, \frac{12}{44}\times 1.043=0.284g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.5670 g of water, \frac{2}{18}\times 0.5670=0.063g of hydrogen will be contained.

Mass of oxygen in the compound = (0.600) - (0.284 + 0.063) = 0.253 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.284g}{12g/mole}=0.0237moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.063g}{1g/mole}=0.063moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.253g}{16g/mole}=0.0158moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0158 moles.

For Carbon = \frac{0.0237}{0.0158}=1.5

For Hydrogen  = \frac{0.063}{0.0158}=3.98\approx 4

For Oxygen  = \frac{0.0158}{0.0158}=1

The ratio of C : H : O = 1.5 : 4 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : O = 3 : 8 : 2

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 8 : 2

Hence, the empirical formula for the given compound is C_3H_8O_2

6 0
3 years ago
Calculate the number of atoms in 4g of bromine molecule.(Br).
KIM [24]

Answer:

\\ N=n * N_{A}

We do not have n - the amount of substance.

n=\frac{m}{M}\\

The molecular weight (M) of Bromine is 80.

n=\frac{4}{80} = 0.05 \text{ mol}

N = 0.05 * 6.02 * 10^{23} = 0.301 * 10^{23}

3 0
3 years ago
What determines the number of possible sub levels?
sp2606 [1]
<span>There are 5 orbitals in the d level. Each orbital holds 2 electrons for a</span>
5 0
3 years ago
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