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alexgriva [62]
3 years ago
14

Calculate the equilibrium constant for the decomposition of water 2h2o(l)  2h2(g) + o2(g) at 25°c, given that g°f (h2o(l)) = –

237.2 kj/mol.
Chemistry
1 answer:
kow [346]3 years ago
3 0

Answer:

2.6 ×10^-42

Explanation:

From

∆G= -RTlnK

∆G= -237.2 KJmol-1 or -237.2×10^3 Jmol-1

R= 8.314 Jmol-1K-1

T= 25°C + 273= 298K

-237.2×10^3= 8.314 × 298 × ln K

ln K= -237.2×10^3/2477.572

K = 2.6 ×10^-42

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How does the law of conservation of mass apply to this reaction C2H4 + O2 > 2H2O + 2CO2
Sindrei [870]
Coefficients are used here to balance the number of elements in the products and reactants. Coefficients are numbers that are placed in front of a chemical formulas in an equation. Hope it's useful.
7 0
3 years ago
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Calculate the value of [CH3OH][CO][H2]2 when all concentrations are 2.4. Keep in mind that the reaction may not be at equilibriu
NikAS [45]

Explanation:

The given reaction will be as follows.

            CO + 2H_{2} \leftrightharpoons CH_{3}OH

So, equilibrium constant for this equation will be as follows.

              K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.

               K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

                       = \frac{2.4}{2.4 \times (2.4)^{2}}

                       = 0.173

Thus, we can conclude that equilibrium constant for the given reaction is 0.173.  

3 0
3 years ago
How many molecules are there in 237 grams of CCl4
Otrada [13]
Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

237g CCl4 (1 mol / 153.81 g ) (6.022 x 10^23 molecules / 1 mol ) = 9.28x10^23 molecules
3 0
3 years ago
4
kondor19780726 [428]

Answer:

.156   M

Explanation:

diluting 25 to 100 cuts the M to 1/4 of the original

1/4 * .625 = .15625

8 0
2 years ago
A certain mass of carbon reacts with 9.53 g of oxygen to form carbon monoxide. ________ grams of oxygen would react with that sa
yawa3891 [41]

Answer: 9.53 *2= 19.06

Explanation:

The law of multiple proportions states that if two elements combines to form more than one compound the ratio of masses of the second element which combines to the fixed mass of the first element will always be the ratios of the small whole numbers.

in case of carbon monoxide, mass of carbon will be the same of mass of oxygen.

But in case of carbon dioxide, if carbon is 9.53 units then oxygen will be twice as that of carbon.

CO2, so 9.53*2= 19.06 grams of oxygen will combine with 9.53 grams of carbon to form carbon dioxide.

3 0
3 years ago
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