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alexgriva [62]
4 years ago
14

Calculate the equilibrium constant for the decomposition of water 2h2o(l)  2h2(g) + o2(g) at 25°c, given that g°f (h2o(l)) = –

237.2 kj/mol.
Chemistry
1 answer:
kow [346]4 years ago
3 0

Answer:

2.6 ×10^-42

Explanation:

From

∆G= -RTlnK

∆G= -237.2 KJmol-1 or -237.2×10^3 Jmol-1

R= 8.314 Jmol-1K-1

T= 25°C + 273= 298K

-237.2×10^3= 8.314 × 298 × ln K

ln K= -237.2×10^3/2477.572

K = 2.6 ×10^-42

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A 3.00-l flask is filled with gaseous ammonia, nh3. the gas pressure measured at 26.0 ∘c is 1.55 atm . assuming ideal gas behavi
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Answer: -

A 3.00-l flask is filled with gaseous ammonia, NH₃. the gas pressure measured at 26.0 ∘c is 1.55 atm . assuming ideal gas behavior, 3.23 grams of ammonia are in the flask

Explanation: -

Volume V = 3.00 L

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We know the value of Universal gas constant R = 0.082 L atm K−1

mol−1

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