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antiseptic1488 [7]
3 years ago
8

Thunderclouds and storms come from which type of front?

Physics
2 answers:
Lena [83]3 years ago
8 0

Thunder clouds and storms are both come from the cold front.

Answer: Option A

<u>Explanation:</u>

The cold front is the zone of transition where the warm air is lifted up by the effect of the cold air. It is actually a displacement. The cold fronts are seen moving from the North West region to the southeast region.

The air behind the cold front is dry and as the name suggests are much colder. Typically, wind becomes gusty as the cold front passes.

So, temperatures fall suddenly and heavy rain occurs, sometimes with hail, lightning, and thunder. Rising warm air in the front creates tubular clouds and thunderstorms.

alekssr [168]3 years ago
3 0

Answer:

I believe it's A. Cold Front.

Hope this helps, Mark as brainiest please. :-)

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Four identical balls are thrown from the top of a cliff, each with the same speed. The
Jlenok [28]

Answer:

the speed and the kinetic energy of the first and fourth ball are equal, while the speed and kinetic energy of the second and third balls are equal

Explanation:

The kinetic energy, K.E. = (1/2) × m × v²

The velocity of the ball, v = u × sin(θ)

Where;

u = The initial velocity of the ball

θ = The reference angle

1) For the ball thrown straight up, we have;

θ = 90°

∴ v = u

The final velocity of the ball as it strikes the ground is v₂ = u² + 2gh

Where;

h = The height of the cliff

∴ K.E. = (1/2) × m × (u² + 2gh)²

2) For the second ball thrown 30° to the horizontal, we have;

K.E. = (1/2) × m × ((u×sin30)² + 2·g·h)² = K.E. = (1/2) × m × ((0.5·u)² + 2·g·h)²

3) For the third ball thrown at 30° below the horizontal, we have;

K.E. = (1/2) × m × ((u×sin30)² + 2·g·h)² = K.E. = (1/2) × m × ((0.5·u)² + 2·g·h)²

4)  For the fourth ball thrown straight down, we have;

K.E. = (1/2) × m × (u² + 2gh)²

Therefore, as the ball strike the ground, the speed and the kinetic energy of the first and fourth ball are equal, while the speed and kinetic energy of the second and third balls are equal

Learn more about object kinetic energy of object if free fall here;

brainly.com/question/14872097

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3 years ago
Landslides are most common in
nikitadnepr [17]

shorelines of the southeast U.S.

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4 years ago
Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road
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Explanation:

It is given that,

    \frac{dx}{dt} = -40 mi/h,     \frac{dx}{dt} = -40 mi/h

The negative sign indicates that x and y are decreasing.

We have to find \frac{dz}{dt}. Equation for the given variables according to the Pythagoras theorem is as follows.

              z^{2} = x^{2} + y^{2}

Now, we will differentiate each side w.r.t 't' as follows.

        2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}

or,          \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As,       \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

                       = \frac{1}{5}(4 \times (-40) + 3 \times (-40))

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Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.

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Answer:

The first statement is false, the Sun has a stronger gravitational pull.

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The first law of motion applies<br> to what?
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