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Gnesinka [82]
1 year ago
6

How could you increase the force advantage of a lever?Select one:a. Make the effort length longer.b. Make the effort length shor

ter.c. Make the lifting length longer.d. Make the effort force larger.
Physics
1 answer:
11Alexandr11 [23.1K]1 year ago
4 0

The ideal mechanical advantage of a lever (IMA) is given by:

IMA=\frac{Le}{Lr}

Where:

Le = Effort of the arm

Lr = Resistance arm.

Therefore, we can increase the force adventage by increasing the effort arm or reducing the load arm

Answer:

a. Make the effort length longer.

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How far will an object move in one second if it average speed is 5m/s?
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When non-metric units were used in the United Kingdom, a unit of mass called the pound-mass (lbm) was employed, where 1lbm=0.453
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Answer:

a) 0.022%

b) 10014.32 lb

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a) Percentage uncertainty would be

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Percent uncertainty is 0.022%

b) For 1 kg uncertainty mass in kg would be

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8 0
3 years ago
A person wants to make a metronome for music practice. He uses a 35-g object attached to a spring to serve as the time standard.
alukav5142 [94]

To develop this problem it will be necessary to apply the concepts related to the frequency of a spring mass system, for which it is necessary that its mathematical function is described as

f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}

Here,

k = Spring constant

m = Mass

Our values are given as,

m = 35g = 35*10^{-3}kg

f = 1 Hz

Rearranging to find the spring constant we have that,

k = (2\pi f \sqrt{m})^2

k = 4\pi^2 f^2 m

k = (4) (\pi)^2 (1) (35*10^{-3})

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7 0
3 years ago
The latent heat of fusion of alcohol is 25 kcal/kg and its melting point is -114 o C. It has a specific heat of 0.60 in its liqu
Elanso [62]

Answer:

Total energy is 170 kJ

Explanation:

Given data:

latent heat of fusion of alcohol is 25 kcal/kg

melting point of alcohol is -114 degree c

specific heat us 0.60 k cal/kg degree c

energy need for 2 kg solid alcohol is

for Melting:

Energy Q is calculated as

Energy, Q = 25 \times 2.0 kg = 50 kJ

Energy required for Heating liquid:

Energy, ΔH = 2.0 kg \times 0.60 \times (100°C) = 120 kJ

Total  energy = (50 kJ + 120 kJ) = 170 kJ

4 0
3 years ago
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