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Gnesinka [82]
9 months ago
6

How could you increase the force advantage of a lever?Select one:a. Make the effort length longer.b. Make the effort length shor

ter.c. Make the lifting length longer.d. Make the effort force larger.
Physics
1 answer:
11Alexandr11 [23.1K]9 months ago
4 0

The ideal mechanical advantage of a lever (IMA) is given by:

IMA=\frac{Le}{Lr}

Where:

Le = Effort of the arm

Lr = Resistance arm.

Therefore, we can increase the force adventage by increasing the effort arm or reducing the load arm

Answer:

a. Make the effort length longer.

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Water waves in a small tank are .06 m long. They pass a given point at a rate of 14.8 waves every three seconds. What is the spe
snow_lady [41]

Answer:

Speed = 0.296m/2

Period = 0.203 s

Explanation:

If by 'long' you mean the wavelength of the waves, then the wavelength \lambda=0.06m.

The frequency f of the waves is 14.8 waves every 3 seconds or

f=14.8/3 =4.33Hz.

Now the relationship between wavelength \lambda, frequency f and speed v of the waves is:

v=\lambda f

We put in the values \lambda=0.06m and f=4.933Hz and get:

\boxed{v=0.06*4.922=0.296m/s}

Now the period T is just the inverse of the frequency, or

T=\frac{1}{f}

\boxed{T=\frac{1}{4.933}=0.203\:seconds }

4 0
3 years ago
The total mass of the wheelbarrow and the road is 80 kg calculate the weight of the wheelbarrow and the road
Alja [10]

Answer:

The weight of the wheelbarrow and the road is 784 N and the force required to lift the wheelbarrow is 784 N.

Explanation:

Given that,

The total mass of the wheelbarrow and the road is 80 kg.

The weight of an object is given by :

W = mg

where

g is acceleration due to gravity

So,

W = 80 × 9.8

= 784 N

So, the force required to lift the wheelbarrow is equal to its weight i.e. 784 N.

7 0
3 years ago
A light-year is the distance that light travels in one year. The speed of light is 3.00 × 108 m/s. How many miles are there in o
Alinara [238K]

Answer:

(a) 5.88\times 10^{12}mi

Explanation:

We have given speed of light c=3\times 10^8m/sec

Given time = 1 year =365 days

We know that in 1 minute = 60 sec

1 hour = 60×60 = 3600 sec

In one day = 24 hour = 24×60×60=86400 sec

So in 365 days = 365×86400=3.1536\times 10^7sec

We know that distance = speed ×time=3.1536\times 10^7\times 3\times 10^8=9.46\times 10^{15}m

We have given that 1 mi = 1609 m

So 9.46\times 10^{15}m=\frac{9.46\times 10^{15}}{1609}=5.88\times 10^{12}miSo option (a) is correct

8 0
3 years ago
If a freely falling rock were equipped with a speedometer, by how much would its speed readings increase with each second of fal
Klio2033 [76]
Its speed reading would increase to 10 m/s every second 
5 0
3 years ago
Air pressure is 1.0 · 105 N/m2, air density is 1.3 kg/m3, and the density of soft drinks is 1.0 · 103 kg/m3. If one blows carefu
natita [175]

Answer:

v = 27.456 m/s

Explanation:

The support pressure needed of the water in the straw can be calculated by the formula

Given that,

P = r*g*h

= 1000*9.8*0.05 Pa.= 490 Pa

This pressure is compensated by 0.5*r*v^2 of the air,

Hence,

0.5*1.3*v^2 = 490

velocity of air blown into the straw =

v = 27.456 m/s

8 0
3 years ago
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