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PolarNik [594]
4 years ago
14

A heating element having a resistance (at its operating temperature) of 148 Ω is connected to a battery having an emf of 523 V a

nd unknown internal resistance. It is found that heat energy is being generated in the resistance of the heating element at a rate of 66.0 W. What is the rate at which heat energy is being generated in the internal resistance of the battery?
Physics
2 answers:
Fudgin [204]4 years ago
7 0

One formula for the power dissipated by a resistor is

Power = (current)² · (resistance)

I have a feeling that this would be a handy formula to use to solve this problem.

66 W = (current)² · (148 Ω)

Current = √(66/148)

Current = 0.668 Ampere

The total power being delivered by the battery is . . .

Power = (voltage) · (current)

Power = (523 volts) · (0.668 Amp)

Total battery power = 349.4 Watts

66 Watts is being dissipated by the heating element.  The rest of the humongous power delivered by the battery is being dissipated by the battery's own internal resistance.

Power = (349.4 - 66)

<em>Power = 283.4 watts</em>

<em></em>

As a working electrical engineer, I'm required to pound on the desk and protest this expensive and unhealthy situation.  

-- The battery is enormous ... 523 V ! ... and must weigh a ton.  

-- The battery itself is using 81% of the power it's being used to deliver.  

-- And all this is just to operate a measly 66W heater !  

-- You can probably get just as much heat out of the heater in the truck you'll need to shlep this battery around to where the heat is needed.

vladimir2022 [97]4 years ago
4 0

Answer:

The correct answer is 283 watts

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(a) Intensity obeys inverse square law from basis of light passing through a given surface.

(b) Gravitation obeys inverse square law from the basis of force between two masses.

(c) The maximum magnitude of the acceleration of the block is 126.75 m/s².

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Intensity is the ratio is ratio of power to area of a given surface.

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