The acceleration would actually be 1.6 m/s^2. Acceleration= final velocity-initial velocity/time taken. When you do that formula it comes out to equal that.
Answer: 1175 J
Explanation:
Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."
Given
Spring constant, k = 102 N/m
Extension of the hose, x = 4.8 m
from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m
Work done =
W = 1/2 k [x(i)² - x(f)²]
Since x(f) = 0, then
W = 1/2 k x(i)²
W = 1/2 * 102 * 4.8²
W = 1/2 * 102 * 23.04
W = 1/2 * 2350.08
W = 1175.04
W = 1175 J
Therefore, the hose does a work of exactly 1175 J on the balloon
In one of the startling coincidences sprinkled throughout
every field of math and science, the moment of maximum
height is popularly referred to as the "high" tide.
<span>F = m*a = 7000kg * 9.8N/kg = 68,600 N.
68,600 N is your answer
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