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Marat540 [252]
3 years ago
8

PLS HELP ASAP (no links)

Physics
1 answer:
jeyben [28]3 years ago
7 0

Explanation:

Sorry I don't know the answer

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When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele
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Answer:

Max kinetic energy for 340 nm wavelength will be 2.238\times 10^{-19}j

Explanation:

In first case wavelength of electromagnetic radiation \lambda =480nm=480\times 10^{-9}m

Plank's constant h=6.6\times 10^{-34}J-s

Maximum kinetic energy = 0.54 eV

Energy is given by E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J

We know that energy is given

E=K_{MAX}+\Phi, here \Phi is work function

So 4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi

\Phi =3.585\times 10^{-19}J

Now wavelength of second radiation = 340 nm

So energy E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J

So K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j

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How is electromagnetic waves useful for cooking food
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Gases tend to deviate from the ideal gas law at
IgorLugansk [536]
<h2>Answer: high pressures</h2>

The Ideal Gas equation is:

P.V=n.R.T  

Where:

P is the pressure of the gas

n the number of moles of gas

R=0.0821\frac{L.atm}{mol.K} is the gas constant

T is the absolute temperature of the gas in Kelvin.  

According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them.

Now, real gases can behave approximately to an ideal gas, under the conditions described above.

However, when <u>temperature is low</u> these gases deviate from the  ideal gas behavior, because the molecules move slowly, allowing the repulsion or attraction forces to take effect.

The same happens at <u>high pressures</u>, because the volume of molecules is no longer negligible.

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Move with constant speed or accelerate and will determine direction
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Find the average net force.
Lerok [7]

Answer:

<h2><em><u>given</u></em></h2>

<em>mass</em><em>=</em><em> </em><em>3</em><em>.</em><em>5</em><em> </em><em>kg</em>

<em>distan</em><em>ce</em><em> covered</em><em>=</em><em> </em><em>0</em><em>.</em><em>4</em><em>m</em>

<em>inital </em><em>speed</em><em> </em><em>=</em><em> </em><em>1</em><em>.</em><em>5</em><em> </em><em>m</em><em>/</em><em>sec</em>

<em>final</em><em> </em><em>speed</em><em> </em><em>=</em><em> </em><em>0</em><em> </em><em>m</em><em>/</em><em>sec</em>

<h2><u><em>To</em><em> </em><em>find</em></u><em> </em></h2>

<em>net</em><em> </em><em>force</em><em> </em>

<h2><em><u>solution</u></em></h2>

<em>formu</em><em>la</em><em> </em><em>for</em><em> </em><em>force</em><em> </em><em>:</em>

<em>\fbox{f = m.a}</em>

<u><em>In</em><em> </em><em>order</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>force </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the </em><em>acceleration</em><em>.</em></u>

<em><u>According</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>third</u></em><em><u> </u></em><em><u>equat</u></em><em><u>ion</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>Kin</u></em><em><u>ematics-</u></em>

<em><u>\bold{ {v}^{2} =  {u}^{2}  + 2as}</u></em>

<em>where</em><em>,</em>

<em>v</em><em>=</em><em> </em><em>fina</em><em>l</em><em> velocity</em>

<em>u</em><em>=</em><em>inita</em><em>l</em><em> Velocity</em>

<em>a</em><em>=</em><em>Acceleration</em>

<em>s</em><em>=</em><em>Distance</em><em> covered</em>

<em><u>put</u></em><em><u> </u></em><em><u>the </u></em><em><u>value</u></em><em><u> in</u></em><em><u> the</u></em><em><u> </u></em><em><u>abo</u></em><em><u>ve</u></em><em><u> </u></em><em><u>equa</u></em><em><u>tion</u></em>

<em>0</em><em>=</em><em> </em><em>(</em><em>1</em><em>.</em><em>5</em><em>)</em><em>²</em><em>+</em><em> </em><em>2</em><em>a</em><em> </em><em>x</em><em> </em><em>0</em><em>.</em><em>4</em>

<em>-</em><em>2.25</em><em>=</em><em> </em><em>0</em><em>.</em><em>8</em><em>a</em>

<em>a</em><em> </em><em>=</em><em> </em><em>-</em><em>2</em><em>.</em><em>2</em><em>5</em><em>/</em><em>0</em><em>.</em><em>8</em>

<em>a</em><em>=</em><em> </em><em>-</em><em> </em><em>2.8125</em><em> </em><em>m</em><em>/</em><em>sec²</em>

<em>now</em><em> </em><em>put</em><em> </em><em>the </em><em>value</em><em> </em><em>0</em><em>f</em><em> </em><em>accleration</em><em> </em><em>in</em><em> </em><em>formu</em><em>la</em><em> </em><em>of</em><em> </em><em>force</em><em> </em>

<h3><u><em>F</em><em> </em><em>=</em><em> </em><em>m</em><em>.</em><em>a</em></u></h3>

<em>F</em><em> </em><em>=</em><em> </em><em>3</em><em>.</em><em>5</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>2</em><em>.</em><em>8</em><em>1</em><em>2</em><em>5</em>

<em>F</em><em>=</em><em> </em><em>-</em><em>9.84375</em><em> </em><em>N</em>

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