The resistance of an ohmic material is given by
where l is the length and a is the cross sectional area. For a circular wire, this area is that of a circle:
Then solving for diameter, d:
Answer:
11.625 Ohm
Explanation:
Let V be the Voltage charge of the loop, as this is constant we know that before the resistor addition the current I is:
V/R1 = 1.9 or V = 1.9R1
After the resistor addition to series R = R1 + 3.1
I = V/R = V/(R1 + 3.1) = 1.5
We can substitute V = 1.9R1
1.9R1 = 1.5R1 + 1.5*3.1
0.4R1 = 4.65
R1 = 4.65/0.4 = 11.625 Ohm
1) 2 kilograms converted into grams is 2000
2) 5200 meters converted into kilometers is 5.2
3) 20 centimeters converted into meters is 0.2
Answer:
6.25 m/s
196 kg/s
Explanation:
The areas of the pipe from big to small:
As the product of speed and cross-section area is constant, the speed in the smaller pipe would be
The mass flow rate would be:
