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3 years ago

How to measure the speed of sound in air?

Physics

1 answer:

Leona [35]3 years ago

8 0

STEP ONE:

Let you and your friend stand as far away as possible from a large reflecting wall and clap your hands rapidly at a regular rate.

STEP TWO:

Adjust this rate until each clap just coincides with the return of an echo of its predecessor, or until clap and echo are heard as equally spaced.

STEP THREE:

Use a stopwatch to find the time between claps, t. Make a rough measurement of distance to the wall, s. Thus the speed of sound, v = 2s/t

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Why would physics be used to study light emitted by a star?

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Answer:

O D.

Explanation:

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3 years ago

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3 years ago

9. Consider the elbow to be flexed at 90 degrees with the forearm parallel to the ground and the upper arm perpendicular to the

mojhsa [17]

Answer:

Moment about SHOULDER ∑ τ = 3.17 N / m,

Moment respect to ELBOW Στ= 2.80 N m

Explanation:

For this exercise we can use Newton's second law relationships for rotational motion

∑ τ = I α

The moment is requested on the elbow and shoulder at the initial instant, just when the movement begins.

They indicate the angular acceleration, for which we must look for the moments of inertia of the elements involved

The mass of the forearm with the included weight is approximately 2.3 kg, with a length of about 50cm

Moment about SHOULDER

∑ τ = I α

I = I_forearm + I_sphere

the forearm can be approximated as a fixed bar at one end

I_forearm = ⅓ m L²

the moment of inertia of the mass in the hand, let's approach as punctual

I_mass = m L²

we substitute

∑ τ = (⅓ m L² + M L²) α

let's calculate

∑ τ = (⅓ 2.3 0.5² + 0.5 0.5²) 10

∑ τ = 3.17 N / m

Moment with respect to ELBOW

In this case, the arm exerts an upward force (muscle) that is about 3 cm from the elbow

Στ = I α

I = I_ forearm + I_mass

I = ⅓ m (L-0.03)² + M (L-0.03)²

let's calculate

i = ⅓ 2.3 0.47² + 0.5 0.47²

I = 0.2798 Kg m²

Στ = 0.2798 10

Στ= 2.80 N m

3 0

3 years ago

How much force is needed to accelerate a 1245 kg car at a rate of 4.25 m/sec^2?

BartSMP [9]

Answer:

F = 5291.25 N

Explanation:

F = Ma so 1245 times 4.25^2 ,, that equals 5291.25 N

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2 years ago

The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminu

antiseptic1488 [7]

C)a powerful magnet.

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3 years ago

Read 2 more answers