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3 years ago

How to measure the speed of sound in air?

Physics

1 answer:

Leona [35]3 years ago

8 0

STEP ONE:

Let you and your friend stand as far away as possible from a large reflecting wall and clap your hands rapidly at a regular rate.

STEP TWO:

Adjust this rate until each clap just coincides with the return of an echo of its predecessor, or until clap and echo are heard as equally spaced.

STEP THREE:

Use a stopwatch to find the time between claps, t. Make a rough measurement of distance to the wall, s. Thus the speed of sound, v = 2s/t

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7. When initially-unpolarized light passes through three polarizing filters, each oriented at 45 degree angles from the precedin

GREYUIT [131]

Answer:

Explanation:

Let the intensity of unpolarised light be I₀ . After passing through the first polarising filter , the intensity is I₀ / 2 .

After second filter , the intensity will be I₀ / 2 x cos²45 = I₀ / 4

After third filter , the intensity will be I₀ / 4 x cos²45 = I₀ / 8 .

So,

1 / 8 the of initial light passes through the last filter .

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3 years ago

a grape and apple and a watermelon are arranged at the corners of a triangle so that each piece of fruit is three meters away fr

777dan777 [17]

-- There are three pairs of mass with gravitational forces between them.

-- The distances between the masses are the same for each pair.

-- The only other quantity that determines the strength of the gravitational
force is the product of the masses.

-- The product of the masses is greatest for the apple and the watermelon,
so the strength of the gravitational force between them is the greatest.

5 0

3 years ago

A wave is moving at the rate of 40 cm/s. Its wavelength is 5 cm. What is the frequency of the wave? INCLUDE THE CORRECT UNIT!

miskamm [114]

Answer:

Solution given:

velocity=40cm/s

wave length=5cm

we have

frequency =velocity/wavelength=40/5=8hertz.

the frequency of the wave is 8 hertz.

8 0

3 years ago

Suppose that the ultrasound source placed on the mother's abdomen produces sound at a frequency 2 MHz (a megahertz is 10^610 6

ella [17]

Answer:

the maximum frequency observed is 2.0044 10⁶ Hz

Explanation:

This is a Doppler effect exercise. Where the emitter is still and the receiver is mobile, therefore the expression that describes the process is

f ’= $f_o \ ( \frac{v \pm v_o}{v} )$

the + sign is used when the observer approaches the source

typical speeds of a baby's heart stop are around 200 m / min

let's reduce to SI units

v₀ = 200 m / min (1 min / 60 s) = 3.33 m / s

let's calculate

f ’= 2 10⁶ ( $\frac{1500 \ \pm 3.33}{1500}$ )

f ’= 2.0044 10⁶ Hz

f ’= 1,9956 10⁶ Hz

therefore the maximum frequency observed is 2.0044 10⁶ Hz

8 0

3 years ago

Which is true about the velocity of sound waves in solids compared to air

tankabanditka [31]

C. Travels slower in solids because the particles are closer together.

4 0

3 years ago

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