describes how the color and texture of a surface affect absorption and reflection of solar radiation?

1 answer:

3 0

Most of the radiation, however, is absorbed by the earth's surface. ... Every surface on earth absorbs and reflects energy at varying degrees, based on its color and texture. Dark-colored objects absorb more visible radiation; light-colored objects reflect more visible radiation.

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Given the mechanism of C5M action, what is the most likely reason that C5M concentrations greater than 2 µM were NOT used by the

Sunny_sXe [5.5K]

Answer:

It can cause a significant negative effects on certain tissues and target cells.

Explanation:

Generally, based on the mechanism of C5M, its presence in any experiment can harm certain tissues and target cells. Therefore, the use of a large amount (in terms of concentration above 2 µM) of C5M will enhance the negative effects of C5M on the surrounding/neighboring tissue as well as the normal division of target cells. That is the reason why a higher concentration was not used in the experimental runs.

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3 years ago

A voltaic cell with an aqueous electrolyte is based on the reaction between Cd2+(aq) and Mg(s), producing Cd(s) and Mg2+(aq). Wr

Monica [59]

Answer : The balanced two-half reactions will be,

Oxidation half reaction (anode) : $Mg(s)\rightarrow Mg^{2+}(aq)+2e^-$

Reduction half reaction (cathode) : $Cd^{2+}(aq)+2e^-\rightarrow Cd(s)$

Thus the overall reaction will be,

$Mg(s)+Cd^{2+}(aq)\rightarrow Mg^{2+}(aq)+Cd(s)$

Explanation :

Voltaic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the galvanic cell or electrochemical cell.

The given redox reaction occurs between the magnesium and cadmium.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The balanced two-half reactions will be,

Oxidation half reaction (anode) : $Mg(s)\rightarrow Mg^{2+}(aq)+2e^-$

Reduction half reaction (cathode) : $Cd^{2+}(aq)+2e^-\rightarrow Cd(s)$

Thus the overall reaction will be,

$Mg(s)+Cd^{2+}(aq)\rightarrow Mg^{2+}(aq)+Cd(s)$

4 0

3 years ago

Read 2 more answers

The Clean Air Act emphasizes that one way to prevent and reduce air pollution is to involve public participation true or false

Anna35 [415]

True hope this helped

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