Good Morning, how are you?
Your answer is C. The moon orbits and rotates the same, so we NEVER see the far side of the moon from earth :)
Have a great day :)
To convert 2030 rad into rev, divide 2030 by 2pie. So final answer will be
2030/2 pie =323.08 revolutions.
Answer:
I am pretty sure it is B My friend hope you are well
Explanation:
Answer:
891 excess electrons must be present on each sphere
Explanation:
One Charge = q1 = q
Force = F = 4.57*10^-21 N
Other charge = q2 =q
Distance = r = 20 cm = 0.2 m
permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)
Using Coulomb's law,
F=[1/4pieo]q1q2/r^2
F = [1/4pieo]q^2 / r^2
q^2 =F [4pieo]r^2
q = r*sq rt F[4pieo]
q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]
q = 1.42614*10^ -16 C
number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19
n =891
891 excess electrons must be present on each sphere
The approximate orbital period of this star is 13 years.
<h3>What is Kepler's third law?</h3>
The square of a planet's period of revolution around the sun in an elliptical orbit is directly proportional to the cube of its semi-major axis, states Kepler's law of periods.
T² ∝ a³
The time it takes for one rotation to complete depends on how closely the planet orbits the sun. With the use of the equations for Newton's theories of motion and gravitation, Kepler's third law assumes a more comprehensive shape:
P² = 4π² /[G(M₁+ M₂)] × a³
where M₁ and M₂ are the two circling objects' respective masses in solar masses.
Learn more about Kepler's third law here:
brainly.com/question/1608361
#SPJ1
