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Kamila [148]
3 years ago
8

describes how the color and texture of a surface affect absorption and reflection of solar radiation?

Physics
1 answer:
Wewaii [24]3 years ago
3 0

Most of the radiation, however, is absorbed by the earth's surface. ... Every surface on earth absorbs and reflects energy at varying degrees, based on its color and texture. Dark-colored objects absorb more visible radiation; light-colored objects reflect more visible radiation.

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7.) What is the relationship between kinetic and potential energy?
Arte-miy333 [17]
We know that potential energy is the energy that is stored within an object while kinetic energy is the energy that is in motion. The connection between the two is that potential energy transforms into kinetic energy
4 0
2 years ago
I need help on US history portfolio but before you help me...
alex41 [277]

Answer:

1. They believed the British were treating the colonists unfairly.

2. The British passed many tax laws that impacted the colonists.

3. The King of England wanted to tax the Colonists without giving them representation in British parliament.

4. The Colonists decided they wanted a better and stronger government, one that would listen to them.

6 0
3 years ago
Two balls of mass m1 and m2, with velocities v1 and v2 collide head on. Is there any way for both balls to have zero velocity af
nordsb [41]

Answer:

Explanation:

As the final Kinetic energy is zero or less than initial kinetic energy, the collision must be inelastic.  

In Inelastic collision both the bodies must stick together as final velocity is zero for both the bodies.

To conserve the momentum, momentum associated before the collision of first must be equal and opposite to the momentum associated with the second ball.

i.e.

m_1v_1=m_2v_2

8 0
3 years ago
A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 rad/
torisob [31]

Answer:

The constant angular acceleration of the wheel is 12.16 rad/s²

Explanation:

Given;

initial angular distance, θ = 28

time of the motion, t = 5 s

initial angular velocity is calculated as;

\omega _i = \frac{\theta}{t} = \frac{28}{5}.\frac{rev}{s}  \ \times \ \ \frac{2 \pi \ rad}{1 \ \ rev} = 35.19 \ rad/s

final angular velocity is given as, \omega _f = 96.0 \ rad/s

The constant angular acceleration is calculated as;

\alpha = \frac{\omega _f - \omega _i}{t} \\\\\alpha = \frac{96 - 35.19}{5} \\\\\alpha =  12.16 \ rad/s^2

Therefore, the constant angular acceleration of the wheel is 12.16 rad/s²

6 0
2 years ago
Help . . . . . . . . . . . . . . . . . . . .
Zigmanuir [339]

Explanation:

Transmission

Reflection

Absorption

Refraction

Diffraction

4 0
2 years ago
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