All categories

3 years ago

describes how the color and texture of a surface affect absorption and reflection of solar radiation?

1 answer:

3 0

Most of the radiation, however, is absorbed by the earth's surface. ... Every surface on earth absorbs and reflects energy at varying degrees, based on its color and texture. Dark-colored objects absorb more visible radiation; light-colored objects reflect more visible radiation.

You might be interested in

3 write the three laws given by kepler.How did they help Newton to arrive at the inverse square law of gravity?

stiv31 [10]

Answer:

Kepler's laws apply: First Law: Planetary orbits are elliptical with the sun at a focus. Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times. Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semimajor axis is the same for all planets.

5 0

3 years ago

A 100.0 mL sample of 1.020 M HCl is mixed with a 50.0 mL sample of 2.040 M NaOH in a Styrofoam cup. If both solutions were initi

I am Lyosha [343]

Answer:

$t_2 = 33.793$

Explanation:

Given data:

0.1 L HCl × 1.020 mol/L = 0.102 mol HCL

0.05 L NaOH × 2.040 mol/L = 0.102 mol NaOH

NaOH + HCl \rightarrow H_2O + NaCl

0.102 mol HCl /1 mol HCl × 1 mol H2O = 0.102 mol H2O

0.102 mol H2O / 1 mol H2O × 57000 J = 5814 J

$V(t ) = V_1+V_2 = 100 + 50 = 150 mL$

M(t)=150*1=150 g

we know that heat energy is given as

$Q = mc(t_2 - t_1)$

where c is specific heat

total energy released is = 57 \times 0.102 = 5.814 kJ

$5814 = 150 \times 4.184 \times (t_2 - 24.53)$

$t_2 = 33.793$

8 0

3 years ago

Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. The initial temperature of the gas is 28.0

mel-nik [20]

Answer:

63.5 °C

Explanation:

The expression for the calculation of work done is shown below as:

$w=P\times \Delta V$

Where, P is the pressure

$\Delta V$ is the change in volume

Also,

Considering the ideal gas equation as:-

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 8.314 J/ K mol

So,

$V=\frac{nRT}{P}$

Also, for change in volume at constant pressure, the above equation can be written as;-

$\Delta V=\frac{nR\times \Delta T}{P}$

So, putting in the expression of the work done, we get that:-

$w=P\times \frac{nR\times \Delta T}{P}=nR\times \Delta T$

Given, initial temperature = 28.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (28.0 + 273.15) K = 301.15 K

W=1770 J

n = 6 moles

So,

$1770\ J=6 moles\times 8.314\ J/ Kmol \times (T_2-301.15\ K)$

Thus,

$T_2=301.15\ K+\frac{1770}{6\times 8.314}\ K$

$T_2=336.63\ K$

The temperature in Celsius = 336.63-273.15 °C = 63.5 °C

<u>The final temperature is:- 63.5 °C</u>

7 0

3 years ago

What is the acceleration of a 1000 kg car subject to a 550 N net force

Xelga [282]

Answer:

The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2

Explanation:

Given:

F = 550 N

m = 1000 kg

To Find:

a = ?

Solution:

So by the equation by Newton's 2nd Law of Motion,

F = m x a

550 N = 1000 kg x a

a = 550 N/ 1000 kg

a = 0.55 m/s^2

Therefore,

The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2

PLEASE MARK ME AS BRAINLIEST!!!

4 0

2 years ago

EXPERTS/ACE and people that wanna help 4 sure only!

mario62 [17]

That first one you have selected (3,-3) works in both equations so it's correct.
good job.

you can do this guess and test method with multiple choice answers. If it works in both equations it is the solution. Otherwise use substitution or elimination to combine the two into one equation in only one variable. Then you can solve for the one variable first and use it to solve for the other.

3 0

2 years ago