Matter that has a fixed composition is a ________. Which is formed by______

Firecrackers A and B are 600 m apart. You are standing exactly halfway between them. Your lab partner is 300 m on the other side

pishuonlain [190]

Answer:

See the explanation

Explanation:

Given:

Distance of Firecrackers A and B = 600 m

Event 1 = firecracker 1 explodes

Event 2 = firecracker 2 explodes

Distance of lab partner from cracker A = 300 m

You observe the explosions at the same time

to find:

does event 1 occur before, after, or at the same time as event 2?

Solution:

Since the lab partner is at 300 m distance from the firecracker A and Firecrackers A and B are 600 m apart

So the distance of fire cracker B from the lab partner is:

600 m + 300 m = 900 m

It takes longer for the light from the more distant firecracker to reach so

Let T1 represents the time taken for light from firecracker A to reach lab partner

T1 = 300/c

It is 300 because lab partner is 300 m on other side of firecracker A

Let T2 represents the time taken for light from firecracker B to reach lab partner

T2 = 900/c

It is 900 because lab partner is 900 m on other side of firecracker B

T2 = T1

900 = 300

900 = 3(300)

T2 = 3(T1)

Hence lab partner observes the explosion of the firecracker A before the explosion of firecracker B.

Since event 1 = firecracker 1 explodes and event 2 = firecracker 2 explodes

So this concludes that lab partner sees event 1 occur first and lab partner is smart enough to correct for the travel time of light and conclude that the events occur at the same time.

8 0

2 years ago

What is the definition of differentiation geology?

UkoKoshka [18]

Any process in which a mixture of materials separates out partially

5 0

3 years ago

Which statement is true about planets with longer orbits in the solar system?

Yakvenalex [24]

Answer:

D They have longer seasons

Explanation:

I think this because the days will be longer so that means that the seasons will change also.

5 0

2 years ago

Read 2 more answers

Block A weighs 14 lb and block B weighs 5 lb If B is moving downward with a velocity (vB)1 = 3 ft/s at t = 0, determine the velo

kolezko [41]

Velocity, va2 = 10.5 ft/s

Explanation:

From the figure:

Length of the cable = Sa + 2Sb = l

∴ vₐ = -2vb

Applying the principle of Impulse and momentum in x-direction

$mv_x_1 + \int\limits^t_t {F_x} \, dt = mv_x_2$

Limit is t1 to t2

$-(\frac{14}{32.2}) (2) (3) - T = \frac{14}{32.2} v_y_2$ -(1)

Applying the principle of Impulse and momentum in y-direction

$mv_y_1 + \int\limits^t_t {F_y} \, dt = mv_y_2$

Limit is t1 to t2

$(\frac{5}{32.2}) (3) - 2T + 3 = -\frac{5}{32.2} \frac{v_y_2}{2}$ -(2)

Solving equation (1) and (2), we obtain

T = 1.6lb

va2 = 10.5 ft/s

8 0

2 years ago

34000×0.4 ---------------- 0.02×200 In scientific notation

VashaNatasha [74]

Answer:

the simplified expression is written as 3.4 x 10³

Explanation:

Given expression;

$\frac{34000\times 0.4}{0.02 \times 200}$

in scientific notation, the expression is simplified as;

$\frac{34000\times 0.4}{0.02 \times 200} = \frac{13600}{4} = 3400 = 3.4 \times 10^3$

Therefore, in scientific notation, the simplified expression is written as 3.4 x 10³

4 0

2 years ago

Matter that has a fixed composition is a ________. Which is formed by_______.

Matter that has a fixed composition is a __. Which is formed by_.