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Alecsey [184]
3 years ago
13

A weight lifter raises a 1600 N barbell to a height of 2.0 meters. How much work was done? W = Fd

Physics
2 answers:
-Dominant- [34]3 years ago
3 0
D) 3200 joules is the answer
Naya [18.7K]3 years ago
3 0

Answer : Work done, W = 3200 Joules.

Explanation :

The force acting on the berbell, F=1600\ N

The height attained by it, h=2\ m

We know that the relation between the work done, force acting and the displacement is given by :

W=F\times d

W=1600\ N\times 2\ m

W=3200\ Joules

The work done will be 3200 Joules.

So, the correct option is (D).

Hence, this is the required solution.

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You are crossing the event horizon of a black hole

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<h3>What happens when you are crossing the event horizon of a black hole?</h3>
  • The point of no return is the black hole's event horizon.
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<h3>Is it possible to endure inside an event horizon?</h3>
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<h3>What occurs beyond the horizon of the event?</h3>
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6 0
2 years ago
High-speed stroboscopic photographs show that the head of a 180 g golf club is traveling at 47 m/s just before it strikes a 46 g
inn [45]

Answer:

47 m/s

Explanation:

golf club mass, mc = 180 g

golf ball mass, mb = 46 g

initial golf club speed, vc1 = 47 m/s

final golf club speed, vc2 = 35 m/s

initial golf ball speed, vb1 = 0 m/s

final golf ball speed, vb2 = ? m/s

The total momentum is conserved, then:

mc*vc1 + mb*vb1 = mc*vc2 + mb*vb2

Replacing with data and solving (dimension are omitted):

180*47 + 46*0 = 180*35 + 46*vb2

vb2 = (180*47 - 180*35)/46

vb2 = 47 m/s

7 0
3 years ago
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zheka24 [161]

Answer:

It increases proportionally

Explanation:

The gravitational force between the Earth and an object on its surface is given by

F=G\frac{Mm}{R^2}

where

G is the gravitational constant

M is the Earth's mass

m is the mass of the object

R is the Earth's radius

In this problem, the Earth's mass is increased, while the diameter (and therefore, the radius) doesn't change. From the equation, we see that the gravitational force is directly proportional to the Earth's mass: therefore, if the mass is increased, the force will increase as well by the same proportion (for example, if the mass is doubled, the force will double as well)

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