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Alecsey [184]
3 years ago
13

A weight lifter raises a 1600 N barbell to a height of 2.0 meters. How much work was done? W = Fd

Physics
2 answers:
-Dominant- [34]3 years ago
3 0
D) 3200 joules is the answer
Naya [18.7K]3 years ago
3 0

Answer : Work done, W = 3200 Joules.

Explanation :

The force acting on the berbell, F=1600\ N

The height attained by it, h=2\ m

We know that the relation between the work done, force acting and the displacement is given by :

W=F\times d

W=1600\ N\times 2\ m

W=3200\ Joules

The work done will be 3200 Joules.

So, the correct option is (D).

Hence, this is the required solution.

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Technician a says that the water pump is a centripetal pump. technician b says that centripetal force is the outward force that
Vaselesa [24]
<span>Technician A is correct about the water pump being a centripetal pump and the definition of the centripetal force given by technician B is wrong. The force that happens on a body moving in a circular path and move towards the centre to which the body is moving is called as centripetal force. So it’s not an outward force.</span>
3 0
3 years ago
A block of mass 0.260 kg is placed on top of a light, vertical spring of force constant 5 200 N/m and pushed downward so that th
abruzzese [7]

After being released, the restoring force exerted by the spring performs

1/2 (5200 N/m) (0.090 m)² = 12.06 J

of work on the block. At the same time, the block's weight performs

- (0.260 kg) <em>g</em> (0.090 m) ≈ -0.229 J

of work. Then the total work done on the block is about

<em>W</em> ≈ 11.83 J

The block accelerates to a speed <em>v</em> such that, by the work-energy theorem,

<em>W</em> = ∆<em>K</em>   ==>   11.83 J = 1/2 (0.260 kg) <em>v</em> ²   ==>   <em>v</em> ≈ 9.54 m/s

Past the equilibrium point, the spring no longer exerts a force on the block, and the only force acting on it is due to its weight, hence it has a downward acceleration of magnitude <em>g</em>. At its highest point, the block has zero velocity, so that

0² - <em>v</em> ² = -2<em>gy</em>

where <em>y</em> is the maximum height. Solving for <em>y</em> gives

<em>y</em> = <em>v</em> ²/(2<em>g</em>) ≈ 4.64 m

4 0
3 years ago
I a liter jar contains 0.5 moles of gas at a pressure of 2 ATM what is the temperature of the gas
sweet [91]

Answer:

<h2>The temperature of the gas is 48.75 Kelvin.</h2>

Explanation:

Using the ideal gas equation as shown

PV = nRT where;

P is the pressure of the gas in ATM

V is the volume of the gas

n is the number of moles

R is the ideal gas constant

T is the temperature in Kelvin

From the formula, T = \frac{PV}{nR}

Given the following parameters V = 1litre, n = 0.5moles. pressure = 2ATM

R = 0.08206 atm L/molK

On substituting to get the temperature we have:

T = \frac{2*1}{0.08206*0.5} \\T = \frac{2}{0.04103}\\T = 48.75Kelvin

5 0
3 years ago
M= 1000 g g= 10 m/s2 h= 10 K.E at GROUND = 400 j M.E = ....... ........J the answer is 400 so plz explain how
Simora [160]

Answer:

M = 500 J

Explanation:

Given that,

Mass, M = 1000 g = 1 kg

Height, h = 10 m

Potential energy is given by :

P = mgh

P = 1×10×10

P = 100 J

The kinetic energy at ground = 400 J

Mechanical energy = sum of kinetic and potential energy

So,

M = 100 + 400

M = 500 J

So, the mechanical energy of the system is 500 J.

4 0
3 years ago
For elevator questions, does the weight of a person increase when the elevator is going up or if it's going down-
TiliK225 [7]

The weight of a person increase when the elevator is going up.

<h3>Weight of the person in the elevator</h3>

The weight of the person in the elevator is calculated as follows;

<h3>When the person is going up</h3>

F = ma + mg

F = m(a + g)

where;

  • a is acceleration of the person
  • g is acceleration due to gravity

<h3>When the person is going down</h3>

F = mg - ma

F = m(g - a)

Thus, the weight of a person increase when the elevator is going up.

Learn more about weight here: brainly.com/question/2337612

#SPJ1

6 0
2 years ago
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