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Ahat [919]
3 years ago
13

Car a has a mass of 5 kg and 10 m/s .cart B has a mass of 10 kg and 5 m/s .which of the following statements best compares the i

nterior of the momenta of the two carts?
Physics
1 answer:
weeeeeb [17]3 years ago
7 0

The two cars have same momentum

Explanation:

The momentum of an object is given by the equation

p=mv

where

m is the mass of the object

v is its velocity

For the car A in this problem,

m = 5 kg

v = 10 m/s

So its momentum is

p_A = (5 kg)(10 m/s) = 50 kg m/s

For car B we have,

m = 10 kg

v = 5 m/s

So its momentum is

p_B = (10 kg)(5 m/s)=50 kg m/s

Therefore, the two cars have same momentum.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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Answer:

A stripe of magnetic information that is affixed to the back of a plastic credit or debit card.

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3 years ago
Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
kumpel [21]

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

Car B has to travel a distance of D_A and d_a

where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

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3 years ago
A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision.
IgorLugansk [536]

Answer:

v₃ = 3.33 [m/s]

Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.

(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}

where:

m₁ = mass of the car = 1000 [kg]

v₁ = velocity of the car = 10 [m/s]

m₂ = mass of the truck = 2000 [kg]

v₂ = velocity of the truck = 0 (stationary)

v₃ = velocity of the two vehicles after the collision [m/s].

Now replacing:

(1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s]

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What distance will a car cover while uniformly accelerating from 12m/s to 26m/in 14 seconds​
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Answer:

Distance = 266m

Explanation:

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a 4m long straight wir that carries acurrent of 0.5A is placed perpendicular to a uniform magnetic field. if the size of magneti
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Answer:

B=0.2T

Explanation:

given required solution

l=4m B=? <em>F</em><em>=</em><em>BIL</em>

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3 years ago
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