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mars1129 [50]
3 years ago
7

The density of an object is dependent upon the object’s mass and ---

Physics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:Volume

Explanation:

Density = mass/ Volume

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Because of surface tension, it is possible, with care, to support an object heavier than water on the water surface. The maximum
boyakko [2]

Answer:

\pi 1 = \frac{h}{l}

\pi 2 = б / l^2gp

\frac{h}{l} = Ф ( б / l^2gp )

Explanation:

<u>Develop a suitable set of dimensionless parameters for this problem</u>

The set of dimensionless parameters for this problem is :

\pi 1 = \frac{h}{l}

\pi 2 = б / l^2gp

\frac{h}{l} = Ф ( б / l^2gp )

and they are using the pi theorem, MLT systems

attached below is a detailed solution

7 0
2 years ago
A simple pendulum is made from a 0.54-m-long string and a small ball attached to its free end. The ball is pulled to one side th
Serga [27]

Answer:

0.37sec

Explanation:

Period of oscillation of a simple pendulum of length L is:

T = 2 π × √ (L /g)

L=length of string 0.54m

g=acceleration due to gravity

T-period

T = 2 x 3.14 x √[0.54/9.8]

T = 1.47sec

An oscillating pendulum, or anything else in nature that involves "simple harmonic" (sinusoidal) motion, spends 1/4 of its period going from zero speed to maximum speed, and another 1/4 going from maximum speed to zero speed again, etc. After four quarter-periods it is back where it started.

The ball will first have V(max) at T/4,

=>V(max) = 1.47/4 = 0.37 sec

3 0
3 years ago
The engine on a fighter airplane can exert a force
DerKrebs [107]
Yes it can because it had lots of force
8 0
3 years ago
A disk shaped grindstone of mass 3.0 kg and radius 8 cm is spinning at 600 rpm. After the power is shut off the frictional torqu
seropon [69]

Answer:

\theta=50\ revolution

Explanation:

It is given that,

Mass of the grindstone, m = 3 kg

Radius of the grindstone, r = 8 cm = 0.08 m

Initial speed of the grindstone, \omega_i=600\ rpm=62.83\ rad/s

Finally it shuts off, \omega_f=0

Time taken, t = 10 s

Let \alpha is the angular acceleration of the grindstone. Using the formula of rotational kinematics as :

\alpha =\dfrac{\omega_f-\omega_i}{t}

\alpha =\dfrac{0-62.83}{10}

\alpha =-6.283\ rad/s^2

Let \theta is the number of revolutions of the grindstone after the power is shut off. Now using the third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta

\theta=\dfrac{\omega_f^2-\omega_i^2}{2\alpha }

\theta=\dfrac{-62.83^2}{2\times -6.283}

\theta=314.15\ radian

\theta=49.99\ revolution

or

\theta=50\ revolution

So, the number of revolutions of the grindstone after the power is shut off is 50.

7 0
3 years ago
Which of the following is NOT a characteristic of noble gases? *
statuscvo [17]

Answer:

solid at room temperature

Explanation:

they are unreactive

3 0
2 years ago
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