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mars1129 [50]
3 years ago
7

The density of an object is dependent upon the object’s mass and ---

Physics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:Volume

Explanation:

Density = mass/ Volume

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Under very dim levels of illumination foveas react to increase the sensitivity of the optic nerve. rods are more light-sensitive
Alex777 [14]

Answer:

rods are more light sensitive than cones.

Explanation:

There are two types of photo receptors in retina of our eyes. 1 Rods and 2 Cones. Rods are about 120 million and they are more sensitive then the cones. But the rods are not sensitive to color. Cones help us in seeing the color and there are about 6 to 7 million cones that provide color sensitivity to our eyes. That is why in the dark or where their are dim levels of illumination rods provide us scotopic vision. Because rods are more light sensitive then the cones.

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4 years ago
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A hammer taps on the end of a 4.0-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two pu
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4 years ago
The kinetic energy of a rotating body is generally written as K=12Iω2, where I is the moment of inertia (also known as rotationa
agasfer [191]

Answer

given,

expression of Kinetic energy of rotating body

K = \dfrac{1}{2}I\omega^2

ω = 34.0 rad/s

Assuming mass of the particle equal to 13 Kg

and perpendicular distance from the particle to the axis is r = 1.25 m

now,

moment of inertia of particle = ?

from the given expression

I= \dfrac{2K}{\omega^2}..............(1)

we know

K = \dfrac{1}{2}mv^2

v = r ω

K = \dfrac{1}{2}mr^2\omega^2

putting value in equation (1)

I= \dfrac{2\dfrac{1}{2}mr^2\omega^2}{\omega^2}

I =mr^2

I =13 \times 1.25^2

I = 20.3125 kg.m²

4 0
3 years ago
A copper wire expand when
o-na [289]

Answer: when heated and for answer dont forget to hit the brainliest

Explanation:

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3 years ago
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the volume of ice block is 2400cm^3 and its density is 0.9 g/cm^3. how much part of it remains above the surface of water when i
stiks02 [169]

Answer:

240 cm³

Explanation:

Weight = Buoyancy

mg = ρVg

m = ρV

(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V

V = 2160 cm³

The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.

4 0
3 years ago
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