The volume of gas that exerts a pressure of 457 mmhg if exerted a pressure of 2.50 atm when its volume was 25.0ml is calculated as follows
by use of Bolyes law formula that is P1V1=P2V2
P1= 457mmhg
V1=?
P1 = 2.50 atm = 2.50 x760 = 1900mmhg
V2= 25,0 ml
V1 from the formula above = P2V2/P1
= 1900mm hg x25 ml/ 457 mm hg = 104 ml
The balanced chemical reaction is:
<span>3N2H4(l)→4NH3(g)+N2(g)
</span>
The amounts given for the N2H4 reactant will be the starting point for our calculations.
2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3
4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3
63.8g N2H4 <span>( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3</span>
Answer:
C = 0.5621J/g°C
Explanation:
Heat lost by metal = Heat gained by water
Heat gained by water;
H = MC ΔT
ΔT = 28 -25 = 3.0°C
M = 130.0g
C = 4.18 J/g°C
H = 130 * 4.18 * 3 = 1639J
Heat lost my metal;
H = MCΔT
ΔT = 100 - 28 = 72°C
M = 40.5g
C = ?
C = H / MΔT
C = 1639 / (40.5 * 72)
C = 0.5621J/g°C
Top: The grasshopper population would begin to have a dramatic increase because of the lack of being eaten if the frogs disappeared and the snakes would decrease in population because of less food availability.
Bottom: All of the organisms in the food chain are equally as important because a drastic change would occur if one disruption was made.
Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and respectively.
Explanation :
Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).
As we are given that:
Fuel value =
Molar mass of pentane = 72 g/mol
Fuel value =
Fuel value = 49.09 kJ/g
Now we have to calculate the fuel density of pentane.
Fuel density = Fuel value × Density
Fuel density = (49.09 kJ/g) × (0.626g/mL)
Fuel density = 30.73 kJ/mL =
Thus, the fuel density of pentane is