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suter [353]
4 years ago
8

Not including the noble gases, which area of the periodic table has the highest electronegativities?

Chemistry
2 answers:
Anna71 [15]4 years ago
8 0
The answer is the upper right Fluorine is the most electronegative. 
alekssr [168]4 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

It is known that when we move across a period from left to right in a periodic table then there will be decrease in size of elements. This is because of addition of electrons into the same sub-shell.

Whereas when we move down a group then there occurs an increase in size of atoms due to addition of new sub-shells.

As electronegativity is the ability of an atom to attract an electron towards itself. Hence, smaller is the size of an atom more will be the ability of its nucleus to attract a proton towards itself. As a result, higher will be its electronegativity.

For example, fluorine is the most electronegative element present in the periodic table.

Thus, we can conclude that upper right area of the periodic table has the highest electronegativities.

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When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
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Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

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