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2 years ago

A block of mass m=3.0 kg is pushed down a 50° incline surface with a force of magnitude F=40 N.

Physics

1 answer:

Sauron [17]2 years ago

7 0

Answer:

I really don't know but please if you find the correct answer tell me because I'm eager to know

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Does the orbital period of a planet depend on the mass of the planet or on the mass of the star that it orbits?

jasenka [17]

Answer:

The orbital period of a planet depends on the mass of the planet.

Explanation:

A less massive planet will take longer to complete one period than a more massive planet.

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2 years ago

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3 years ago

Why do people put rough strips in their bathtubs?

krok68 [10]

Answer:

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Explanation:

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3 years ago

A chipmunk with a mass of 2 kg sits on a branch that is 10 m off the ground.

vlada-n [284]

I hope I'm not too late.

GPE = mass * gravity * height

GPE = 2 kg * 9.8 m/s * 10

GPE = 196 Joules

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3 years ago

Yo-Yo man releases a yo-yo from rest and allows it to drop, as he keeps the top end of the string stationary. The mass of the yo

patriot [66]

To solve this problem it is necessary to use the conservation equations of both kinetic, rotational and potential energy.

By definition we know that

$KE + KR = PE$

Where,

KE =Kinetic Energy

KR = Rotational Kinetic Energy

PE = Potential Energy

In this way

$\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh$

Where,

m = mass

v= Velocity

I = Moment of Inertia

$\omega =$ Angular velocity

g = Gravity

h = Height

We know as well that $\omega = v/r$ for velocity (v) and Radius (r)

Therefore replacing we have

$\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh$

$[tex]h= \frac{1}{2} \frac{v^2}{g} +\frac{1}{2} \frac{I}{mg}(\frac{v}{r})^2$ [/tex]

$h= \frac{1}{2}v^2 ( \frac{1}{g} +\frac{I}{mg}\frac{1}{r^2} )$

$h= \frac{1}{2}0.75^2 ( \frac{1}{9.8} +\frac{2.9*10^{-5}}{(0.056)(9.8)}\frac{1}{(0.0064)^2} )$

$h = 0.3915m$

Therefore the height must be 0.3915 for the yo-yo fall has a linear speed of 0.75m/s

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3 years ago