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Nastasia [14]
3 years ago
10

What is the smallest particle of an element that still has the same chemical properties?

Chemistry
1 answer:
egoroff_w [7]3 years ago
7 0
The answer is an atom! :)
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Name Formula: Lead (II) Oxide<br> F) Pb2O<br><br> G) PbO2<br><br> H) PbO<br><br> I) Pb2O2
garik1379 [7]

Answer:

PbO is the Answer

Explanation:

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What does food provide to organisms?<br><br> A-homeostasis<br> B-shelter<br> C-energy<br> D-air
leva [86]
Energy would be the correct answer
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The name of Earth's single, huge continent from over 250 million years ago is (1 point)
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Hydrogen and iodine react to form hydrogen iodide, like this: H_2 (g) + I_2 (g) rightarrow 2 HI(g) Also, a chemist finds that at
telo118 [61]

This is an incomplete question, here is a complete question.

Hydrogen and iodine react to form hydrogen iodide, like this:

H_2(g)+I_2(g)\rightarrow 2HI(g)

Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen, iodine, and hydrogen iodide has the following composition:

Compound            Pressure at equilibrium

H_2                                   61.8 atm

I_2                                    46.5 atm

HI                                  52.3 atm

Calculate the value of the equilibrium constant K_p for this reaction. Round your answer to 2 significant digits.

Answer : The value of equilibrium constant K_p for this reaction is, 0.952

Explanation :

The given chemical reaction :

H_2(g)+I_2(g)\rightarrow 2HI(g)

The expression of K_p for above reaction follows:

K_p=\frac{(P_{HI})^2}{P_{H_2}\times P_{I_2}}

We are given:

P_{H_2}=61.8atm

P_{I_2}=46.5atm

P_{HI}=52.3atm

Putting values in above equation, we get:

K_p=\frac{(52.3)^2}{61.8\times 46.5}\\\\K_p=0.952

Therefore, the value of equilibrium constant K_p for this reaction is, 0.952

7 0
3 years ago
One liter of air contains about 0.21 L of oxygen. When filled, the human lungs hold about 6.0 L of air. How much oxygen is in th
masya89 [10]
Since we are told that 1L of air contains 0.21L of oxygen, you can use the conversion (0.21L O₂)/(1L air).  That means that you can just multiply 6.0L by 0.21L to get 1.26L of O₂.
that means that the lungs can hold about 1.26L of oxygen.
I hope this helps.  Let me know if anything is unclear.
4 0
3 years ago
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