Guys can you please help me with this

A block pushed along the floor with velocity v0xv0x slides a distance dd after the pushing force is removed. If the mass of the

Volgvan

Answer:

There is no change in distance

Explanation:

Given that block slides a distance dd with initial velocity $v_{ox}$ $v_{ox}$

Work energy theorem states that Work done W is the difference between final kinetic energy $KE_{f}$ and initial kinetic energy $KE_{i}$

W = $KE_{f}$ - $KE_{i}$ ...........(equation 1)

In the given problem, the work is done by frictional force

Hence the work done is given by

$W_{Friction}$ = - $F_{Friction}$ x dd

$F_{Friction}$ is negative since it is resistive force and dd is the distance

$W_{Friction}$ = - μ mg X dd

where μ is coefficient of friction.

Also we know that Kinetic energy KE = $\frac{1}{2}$ $mv^{2}$

$KE_{f}$ = 0 since final velocity is zero

$KE_{i}$ = $\frac{1}{2}$ $m(v_{ox} v_{ox}) ^{2}$

Substituting the corresponding values equation 1 becomes

-μ mg x dd = 0 - $\frac{1}{2}$ $m(v_{ox} v_{ox}) ^{2}$

dd= $\frac{(v_{ox}v_{ox} )^{2} }{2g}$ x (1/μ) ........... (equation 2)

To find distance when mass of block is doubled and initial velocity is not changed:

Equation 2 shows that the distance dd is independent of mass, therefore there is no change in distance.

5 0

3 years ago

The force that moving, charged particles exert on one another is called

soldi70 [24.7K]

Electromagnetic force.

Hope I helped :-)

6 0

3 years ago

Four 50-g point masses are at the corners of a square with 20-cm sides. What is the moment of inertia of this system about an ax

deff fn [24]

Answer:

moment of inertia I ≈ 4.0 x 10⁻³ kg.m²

Explanation:

given

point masses = 50g = 0.050kg

note: m₁=m₂=m₃=m₄=50g = 0.050kg

distance, r, from masses to eachother = 20cm = 0.20m

the distance, d, of each mass point from the centre of the mass, using pythagoras theorem is given by

= (20√2)/ 2 = 10√2 cm =14.12 x 10⁻² m

moment of inertia is a proportion of the opposition of a body to angular acceleration about a given pivot that is equivalent to the entirety of the products of every component of mass in the body and the square of the component's distance from the center

mathematically,

I = ∑m×d²

remember, a square will have 4 equal points

I = ∑m×d² = 4(m×d²)

I = 4 × 0.050 × (14.12 x 10⁻² m)²

I = 0.20 × 1.96 × 10⁻²

I = 3.92 x 10⁻³ kg.m²

I ≈ 4.0 x 10⁻³ kg.m²

attached is the diagram of the equation

7 0

3 years ago

A CG amplifier using an NMOS transistor for which gm = 2 mA/V has a 5-k drain resistance RD and a 5-k load resistance RL. The am

arlik [135]

Answer: Input Resistance (Rin) = 500 ohms , overall voltage Gain (GV) = 2 volts / volts , ID = 4/9 = 0.44 A

Explanation:

5 0

3 years ago

What do the elements in group 17 of the periodic table have in common

yulyashka [42]

They are toxic and all non metals

7 0

3 years ago