Answer: Yes, it will be around 40ppm(at steady state)
Explanation:
The above question can be solved by performing material balance of CO in the building. The material balance equation is given by, Rate of change of CO in the building = Rate of inflow of CO into the building - Rate of outflow of CO from the blood
Answer:
Absolute pressure= 57 KPa
Explanation:
Given that
Vacuum gauge pressure = 35 KPa
Atmospheric pressure = 92 KPa
We know that
Absolute pressure=Atmospheric pressure + gauge pressure
But we should remember that Vacuum gauge pressure is also called negative gauge pressure.So when given that pressure is vacuum gauge then subtract gauge pressure from atmospheric pressure instead of addition.
So now by putting the values
Absolute pressure=Atmospheric pressure - Vacuum gauge pressure
Absolute pressure=92 - 35 KPa
Absolute pressure= 57 KPa
Answer:
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Explanation:
Answer: hello attached below is the properly written chain reaction to your question
answer :
d[NO] / dt = ![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] + K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20%2B%20K_%7B3f%7D%5BN%5D%5BOH%5D)
d[N] / dt = ![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] - K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20-%20K_%7B3f%7D%5BN%5D%5BOH%5D)
Explanation:
<u>write out expressions for d[NO] / dt and d[N] / dt</u>
Given :
properly written chain reaction ( attached below)
Expression for d[NO] / dt can be written as
![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] + K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20%2B%20K_%7B3f%7D%5BN%5D%5BOH%5D)
Expression for d[N] / dt can be written as
![k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] - K_{3f}[N][OH]](https://tex.z-dn.net/?f=k_%7B1f%7D%20%5BO%5D%20%5BN_%7B2%7D%5D%20%2B%20K_%7B2f%7D%20%20%5BN%5D%5BO_%7B2%7D%20%5D%20-%20K_%7B3f%7D%5BN%5D%5BOH%5D)
Answer:
156.0 ksi
Explanation:
The formula of compressive strength is CS = F / A
where F is the force or load while A is the cross-sectional area
Given the inertia Ag = 35.1 in^4 , which is less than 40, the steel has a short column.
E = 29000 ksi
L = 12ft
r = 2.69 in
therefore;
CS = π^2 E / (kL^2/r)^2
= π^2 29000 / (0.8 x 12^2 / 2.69)^2
= 286292.756 / 1834.4089 = 156 ksi