what do you mean? explain what you r trying to dsay
Answer:
weight = mg
= 2 X 9.8 (g = 9.8m/s^2)
= 19.6 N is the correct answer
<u>Answer:</u>
<em>5 molecules of oxygen will be present
</em>
<u>Explanation:</u>
<em>In this reaction combustion is taking place hence there must be presence of oxygen in it.
</em>
We don't know the initial amount of carbon molecules in hydrogen molecules present hence the equation goes:-
Mass of fuel 16.74 grams, Mass of carbon dioxide is 1198 gram and water is 0.0654 remaining mass of fuel is 16.70 g. Hence amount of fuel used up is 0.04 gram
<em>
</em>
<em>Weight of products is 0.1852 and weight of oxygen is 0.1452
</em>
<em>No of molecules will be 
molecules
</em>
Answer: The question has some details missing. here is the complete question ; An analytical chemist is titrating 88.4 mL of a 0.2700 M solution of ammonia (NH3 with a 0.4300 M solution of HNO3. The pK, of ammonia is 4.74 Calculate the pH of the base solution after the chemist has added 66.3 mL of the HNO3 solution to it . Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution
Explanation:
Given ;
- number of moles of base = 88.4 x 0.2700 = 23.868
- number of moles of acid = 0.4300 x 66.3 = 28.509
- This was after the equivalence point, as such net moles of acid = 28.509 - 23.868 = 4.641mol
- total volume of solution = 88.4 + 66.3 = 154.7mL
- Concentration of Acid = moles/volume = 4.641/154.7 = 0.03M
- From pH = -log[H^+] = -Log[0.03]
Answer: Metalloids
Explanation:
The dark “stair step” line on the right side of the periodic table is where the metalloids are. Metalloids “touch” the SSL. (Stair step line)
The metals are to the left of the SSL and the non metals are to the right of the SSL.
