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Alinara [238K]
3 years ago
15

From 1995-2005, the hourly pay for lifeguards at an outdoor swimming pool increased by 2% per year. The hourly pay, P(t), in dol

lars, t yr after 1995 is given by P(t)=5.60(1.02)t. What was the hourly pay for the lifeguards in 2,001?
Mathematics
1 answer:
12345 [234]3 years ago
7 0

Answer:

The hourly pay for the lifeguards in 2001 was of $6.31.

Step-by-step explanation:

The hourly pay, in dollars, in t years after 1995, is given by the following equation:

P(t) = 5.60(1.02)^{t}

What was the hourly pay for the lifeguards in 2,001?

2001 is 2001 - 1995 = 6 years after 1995. So this is P(6).

P(t) = 5.60(1.02)^{t}

P(6) = 5.60(1.02)^{6} = 6.31

The hourly pay for the lifeguards in 2001 was of $6.31.

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You begin by drawing your trend line. You want your trend line to follow your data. You want to have roughly half your data above the line and the other half below the line, like this:

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Step 2: Locate two points on the line.

Your next step is to locate two points on the trend line. Look carefully at your trend line and look for two easy to figure out points on the line. Ideally, these are points where the trend line crosses a clearly identifiable location.

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