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asambeis [7]
3 years ago
11

How many significant figures are there in 1.01400?

Chemistry
1 answer:
taurus [48]3 years ago
7 0

Answer:

I think it's 4

Explanation:

Because the last two zeros won't be needed

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Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc
marysya [2.9K]

Explanation:

1) 2 Al(s) + 2 NaOH(aq) + 6 H_2O(l) \longleftrightarrow 2 Na[Al(OH)_4](aq) + 7 H_2(g)

Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{11}=0.091

2) H_2O(l) + SO_3(g) \longleftrightarrow H_2SO_4 (aq)

Kc=\frac{[H_2SO_4]}{[SO_3]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{0.0123}=81.3

3)  P_4(s) + 3 O_2(g) \longleftrightarrow P_4O_6(s)

Kc=\frac{1}{[O_2]^3}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{1.56}=0.641

5 0
3 years ago
Give the reason for the evaporation of the solution to dryness with 6 m hcl in the first procedure of the copper-arsenic group a
SCORPION-xisa [38]
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Evaporation occurred between the reaction of the hydrochloric acid and the arsenic group because there is a formation of gas. A liquid is cooled if condensation exceeds evaporation. This is because the cooling of the liquid decreases the kinetic energy of the molecules. Their movement is being restricted by the colder temperature. The molecules tend to be closer with each other. Also, because of their restricted movement, the liquid may turn into solid due the colder temperature. An example of this is the cooling of liquid water by placing it into the refrigerator into solid water (ice).</span>
4 0
3 years ago
How do protons determine element identity
Butoxors [25]

Answer:

The number of protons also determines the identity of the element. ... Since the atom is electrically neutral, the number of electrons must equal the number of protons.

4 0
2 years ago
In the engineering design process what do engineers do immediately after testing a prototype
mote1985 [20]

Answer:

Iterate to improve the solution

Explanation:

apex

5 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Yanka [14]

Answer:

Mass of carbon dioxide produced = 52.8 g

Explanation:

Given data:

Mass of carbon react = 14.4 g

Mass of oxygen = 56.5 g

Mass of oxygen left = 18.1 g

Mass of carbon dioxide produced = ?

Solution:

C + O₂     →      CO₂

Number of moles of C:

Number of moles = mass/ molar mass

Number of moles = 14.4 g/ 12 g/mol

Number of moles = 1.2 mol

18.1 g of oxygen left it means carbon is limiting reactant.

Now we will compare the moles of C with CO₂.

                       C             :         CO₂

                        1             :          1

                      1.2           :          1.2

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.2  mol × 44 g/mol

Mass = 52.8 g

8 0
3 years ago
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