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kari74 [83]
2 years ago
14

Identify the names, charges, and location of three types of subatomic particles that make up an atom.

Physics
2 answers:
Eva8 [605]2 years ago
3 0

Answer:Proton (charge of +e, in the nucleus), Neutron (0 charge, in the nucleus), and Electron (charge of –e, outside the nucleus).Nov 13, 2015

Explanation: YA

vredina [299]2 years ago
3 0

Protons are positive and in the center ( nucleus)


Neutrons have no charge and are also in the center (nucleus)


Electrons are negative and orbit around the nucleus

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A beam of light of two different wavelengths enters a pane of glass 3.2 mm thick at an angle of incidence of 59°. The indices of
Anuta_ua [19.1K]

Answer:

d = 0.125 mm

Explanation:

using snell's law

\dfrac{sin\ i}{sin\ r} = \dfrac{n_2}{n_1}

r = sin^{-1}(\dfrac{n_1sin\ i }{n_2})

n₁ = 1 for air

r = sin^{-1}(\dfrac{sin\ 59^{\circ} }{1.5})

r = 25.09⁰

displacement of color would be

d = t\dfrac{sin(i-r)}{cosr}\\d= 3.2\dfrac{sin(59-25.09)}{cos25.09}\\d= 1.932 mm

for second color

using snell's law

\dfrac{sin\ i}{sin\ r} = \dfrac{n_2}{n_1}

r = sin^{-1}(\dfrac{n_1sin\ i }{n_2})

n₁ = 1 for air

r = sin^{-1}(\dfrac{sin\ 59^{\circ} }{1.53})

r = 22.58°

displacement of color would be

d = t\dfrac{sin(i-r)}{cosr}\\d= 3.2\dfrac{sin(59-22.58)}{cos22.58}\\d= 2.057 mm

hence, separation is

d = 2.057 - 1.932

d = 0.125 mm

8 0
4 years ago
The magnetosphere of Jupiter is
BartSMP [9]

Answer:

d. a large region outside Jupiter occupied by its magnetic field and filled with high-energy charged particles.  

Explanation:

A magnetic field is generated by the movement of a charged particle in the space around it. For the case of Jupiter its magnetic field is created by the liquid metallic hydrogen in its core.

So the magnetosphere is just the magnetic field around a planet, which interacts with high-energy charged particles (for example: Cosmic Rays).

Magnetospheres protect planets from the extreme radiation coming from stars or another interstellar source.      

3 0
3 years ago
Two argon atoms form the molecule Ar2 as a result of a van der Waals interaction with U0 = 1.68×10-21 J and R0= 3.82×10 the freq
mel-nik [20]

Answer:

\mathbf{f_o =1.87 \times 10^{11} \ Hz}

Explanation:

From the given information:

The elastic potential energy can be calculated by using the formula:

U_o = \dfrac{1}{2}kR_o^2

Making K the subject;

K = \dfrac{2 U_o}{R_o^2}

k = \dfrac{2\times 1.68 \times 10^{-21}}{(3.82\times 10^{-10})^2}

k = 2.3 × 10⁻² N/m

Now; the frequency of the small oscillation can be determined by using the formula:

f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{k}{m}}

where;

m = mass of each atom = 1.66 × 10⁻²⁶ kg

f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{2.3 \times 10^{-2} N/m}{1.66 \times 10^{-26} \ kg}}

\mathbf{f_o =1.87 \times 10^{11} \ Hz}

6 0
3 years ago
Difference between displacement and vector quantity
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The only 'difference' is that they are different categories.

It's like asking "What's the difference between Susie and girl ?"

Or "What's the difference between Cadillac and car ?"

Displacement <em>IS</em> a vector quantity.

5 0
3 years ago
A cyclist is riding his bike up a mountain trail. When he starts up the trail , he is going 8 m/s. As the trail gets steeper, he
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Acceleration = (change in speed) / (time for the change)

change in speed = (speed at the end) - (speed at the beginning)

Our cyclist's change in speed = (3 m/s) - (8 m/s) = -5 m/s

Acceleration = (-5 m/s) / (60 seconds)

<em>Acceleration = -1/12 m/s²</em>

7 0
4 years ago
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