Answer:
16.12 V
Explanation:
Ohms law explains or portrays the relationship between the voltage (V), current (I) and resistance (R). This is represented using the equation as follows:
V = IR
Where;
V = voltage (Volts)
I = current (amperes)
R = resistance (ohms)
According to the information provided in the question, resistance (R) = 13 Ohm, current (I) = 1.24 Amperes, V = ?
V = 13 × 1.24
V = 16.12 V
Answer:
587.5 L (Option A)
Explanation:
The reaction is:
2 C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
We know that in STP conditions 1 mol of any gas is contained in 22.4L
Then, we can make a rule of three, to determine the moles of produced carbon dioxide.
22.4L is the volume for 1 mol
376 L will be the volume for (376 . 1) 22.4 = 16.78 moles at STP conditions.
Stoichiometry is 16:25.
16 moles of CO₂ are produce by the reaction of 25 moles of O₂
Then, 16.78 moles of CO₂ were produced by (16.78 . 25) /16 = 26.2 moles.
Now, the rule of three again.
1 mol of oxygen gas is contained at 22.4L, at STP conditions
26.2 moles might be contained at (26.2 . 22.4)/1 = 587.5 L
Answer:
The mol fraction of cyclohexane in the liquid phase is 0.368
Explanation:
Step 1: Data given
Mass of cyclohexane = 25.0 grams
Mass of 2-methylpentane = 44.0 grams
Temperature = 35.0 °C
The pressure of cyclohexane = 150 torr
The pressure of 2-methylpentane = 313 torr
The pressure we only need for the mole fraction in gas phase.
Step 2: Calculate moles of cyclohexane
Moles cyclohexane = mass cyclohexane / molar mass
Moles cyclohexane = 25.0 g / 84 g/mol = 0.298 mol of cyclohexane
Step 3: Calculate moles of 2-methylpentane
Moles = 44.0 grams / 86 g/mol = 0.512 mol of 2-methylpentane
Step 4: Calculate mole fraction of cyclohexane in the liquid phase
Mole fraction of C6H12:
0.298 / (0.298 + 0.512) = 0.368
The mol fraction of cyclohexane in the liquid phase is 0.368
The answer is 27 grams. Hope it helps
Answer:
even though I am missing the question I believe that the correct answer to the question is; <em>his cats will be brown (Dominant)</em>
Explanation:
this statement is true to the fact that on of his cats has the homozygous dominant gene BB. For their to be a chance of a white cat as an offspring both cats would either have to be Hetrozygous (Bb) or Homozygous recesssive (bb)
