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dimaraw [331]
3 years ago
15

How many molecules are in 9.8 grams of calcium

Chemistry
1 answer:
solniwko [45]3 years ago
7 0
Molar mass of Calcium ( Ca ) = 40.078 g/mol

Number of moles in 9.8 grams :

1 mole Ca -----------> 40.078 g
mole Ca -------------> 9.8 g

moles Ca = 9.8 / 40.078

moles Ca = 0.2445 moles

number of molecules:

1 mole ----------------> 6.02x10²³ molecules
0.2445 moles --------> ?

= 0.2445 * 6.02x10²³

= 1.47x10²³ molecules

hope this helps!.

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Answer:

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

Mass of NaOH = x

Molar mass of NaOH = 40 g/mol

Volume of the NaOH solution =  450 mL =- 0.450 L ( 1 ml = 0.450 L)

Molarity of the solution of NaOH = 0.250 M

Molarity=\frac{1.248 g}{26 g/mol\times 0.9102254 L}=0.528 mol/L

0.250 M=\frac{x}{40 g/mol\times 0.450 L}

Solving for x:

x = 4.5 g

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

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