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kkurt [141]
3 years ago
12

HELP PLEASE I need help with these 2 chem questions asap i would gladly appreciate it :)

Chemistry
1 answer:
madreJ [45]3 years ago
5 0
10) You need to find the atomic mass of every element, which you can get from any periodic table.

a) 6.02x10^23 atoms of Mg

Atomic mass of Mg = 24.3 g/mol

# of mols = 6.02 x 10^23 atoms / 6.02 x 10^23 atoms/mol = 1 mol

mass = 1 mol x 24.3 g/mol = 24.3 g

b) 3.01x10^23 formula units of Ca Cl2

Atomic masses

Ca: 40 g/mol
Cl: 35.5 g/mol

Formula mass: 40g/mol + 2x 35.5g/mol = 111 g/mol

# of mols = 3.01 x 10^23 / 6.02 x 10^23 = 0.5 mol

mass = 0.5 mol x 111 g/mol = 55.5 g


c) 12.4 x 10^15 molecules of CH2O

formula mass = 12 g/ mol + 2 g/mol + 16 g/mol = 30 g/mol
# of mols

mass = [12.4 x 10^15 / 6.02 x 10^23]mol x 30 g/mol  = 2.1 x 10 ^(-8) g

3)

a) The polar solute is dissolved in water  which is a polar solvent, while the non polar solute is not dissolved in water. This is a  rule in chemistry: polar solvents dissovle polar soultes and non polar solvents dissolve non polar soluted.

The extremes of the polar molecules are easily solvated by the water molecules.

b) KI is an ionic compound, which implies that it will ioinize (separare in iones) in water, being in this way be dissolved, while the CO2, which is no polar, will not be easily dissolved in water under normal conditions

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The molar mass of an element is the mass of one
allochka39001 [22]

Answer:

  • <em>The molar mass of an element is the mass of </em><u>one mole of atoms of the element.</u>

Explanation:

<em>The molar mass of an element </em>is its atomic mass, i.e.  the mass in grams of one mole of atoms of the element.

Remember 1 mol is approximately 6.022 × 10²³.

So, 1 mol of atoms is 6.022 × 10²³ atoms.

The molar mass is an average: it is the weighted average mass of the natural isotopes of the element, taking into account their relative abundance.

For example, the molar mass or atomic mass of carbon is 12,0107 g/mol, instead of 12.0000, becasue carbon exists in several forms (isotopes), and so the weighted average is not a whole number.

7 0
2 years ago
At room temperature (208C) and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha
Ugo [173]

Total density of filled ball with nitrogen gas: \frac{0.12G+0.6524g}{0.560L} = 1.3792g/L

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = d_4=1.165g/L

Mass of the nitrogen gas : 1.165g/L \times 0.560L = 0.6524g

Learn more about Mass and Density here:

brainly.com/question/10821730

#SPJ4

4 0
1 year ago
A hiker climbs a hill. How does the potential energy of the hiker change as she climbs higher?
zloy xaker [14]
The answer should be A
6 0
3 years ago
The hydrogen atom is not actually electronegative enough to form bonds to xenon. were the xenon-hydrogen bond to exist, what wou
Marat540 [252]

Answer : The structure of XeH_4 will be square-planar.

Explanation :

In the given molecule XeH_4, 'Xe' is the central atom and 'H' is the terminal atom.

Xenon has 8 valence electrons and hydrogen has 1 valence electron. Therefore, the total number of valence electrons are 8 + 4(1) = 12 electrons.

The number of electrons used in Xe-H bonding = 8 electrons

The remaining electrons which are used as lone pair on central atom (Xe) = 12 - 8 = 4 electrons

There are 4 bonding pairs and 2 lone pairs of electrons, they will be arranged in the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. The resulting structure will be square-planar.

The structure of XeH_4 is shown below.

5 0
2 years ago
A gas sample with a volume of 1,500 cm® is heated from -65 °C to 75 °C. Assuming the
djverab [1.8K]

Answer:

V₂ = 2509.62 cm³

Explanation:

Given data:

Initial volume = 1500 cm³

Initial temperature = -65°C (-65 + 273 = 208 K)

Final temperature = 75°C ( 75 +273 = 348 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1500 cm³ × 348 K / 208 k

V₂ = 522000 cm³.K / 208 k

V₂ = 2509.62 cm³

7 0
2 years ago
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