3 years ago

The long-term weather patterns that are typical in a location are the location's .

Physics

2 answers:

Serjik [45]3 years ago

6 0

The long-term weather patterns that are typical in a location are the location's (Climate).

djyliett [7]3 years ago

4 0

Is the locations climate :)

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constant force F=5i+5j−1kF=5i+5j−1k is applied to an object that is moving along a straight line from the point (−5,−3,−4)(−5,−3

meriva

Answer:

W = 71J

Explanation:

Given force F = (5i+5j−1k)N

d = Δr

r1 = (−5,−3,−4)m

r2 = (2,5,0)m

Δr = r2 – r1 = (2-(-5), 5-(-3), 0-(-4))

Δr = (2+5, 5+3, 0+4) = (7i+ 8j +4k)m

W = F•d = (5i+5j−1k)•(7i+ 8j +4k)

W = 5×7 + 5×8 +-1×4 = 35 + 40 - 4

W = 71J

6 0

3 years ago

A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas

vredina [299]

Answer:

464.69 m

Explanation:

First car

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2$

Second car

Distance = Speed × Time

$\text{Distance}=25.7t$

Here, the time taken and the distance traveled will be the same

Equating the two equations

$1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s$

So, the first would have to move $1.42t^2=1.42\times 18.09^2=464.69\ m$ in order to overtake the second car.

7 0

4 years ago

A 51.0 kg cheetah accelerates from rest to its top speed of 31.7 m/s. HINT (a) How much net work (in J) is required for the chee

andrey2020 [161]

(a) $2.56\cdot 10^4 J$

The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:

$W= \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$

where

m = 51.0 kg is the mass of the cheetah

u = 0 is the initial speed of the cheetah (zero because it starts from rest)

u = 31.7 m/s is the final speed

Substituting, we find

$W=\frac{1}{2}(51.0 kg)(31.7 m/s)^2 - \frac{1}{2}(51.0 kg)(0)^2=2.56\cdot 10^4 J$

(b) 6.1 cal

The conversion between calories and Joules is

1 cal = 4186 J

Here the energy the cheetah needs is

$E=2.56\cdot 10^4 J$

Therefore we can set up a simple proportion

$1 cal : 4186 J = x : 2.56\cdot 10^4 J$

to find the equivalent energy in calories:

$x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal$

3 0

3 years ago

Our sun and the planet Earth have what type of force acting between them?

Mnenie [13.5K]

I think the answer is strong force.

4 0

3 years ago

The turbines can be seen inside this hydroelectric dam. Why are they located at that particular height?

Yakvenalex [24]

Answer:

Explanation:

the answer is number three

5 0

4 years ago

Read 2 more answers