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DochEvi [55]
3 years ago
11

constant force F=5i+5j−1kF=5i+5j−1k is applied to an object that is moving along a straight line from the point (−5,−3,−4)(−5,−3

,−4) to the point (2,5,0).(2,5,0). Find the work done if the distance is measured in meters and the force in newtons. Include units in your answer.
Physics
1 answer:
meriva3 years ago
6 0

Answer:

W = 71J

Explanation:

Given force F = (5i+5j−1k)N

d = Δr

r1 = (−5,−3,−4)m

r2 = (2,5,0)m

Δr = r2 – r1 = (2-(-5), 5-(-3), 0-(-4))

Δr = (2+5, 5+3, 0+4) = (7i+ 8j +4k)m

W = F•d = (5i+5j−1k)•(7i+ 8j +4k)

W = 5×7 + 5×8 +-1×4 = 35 + 40 - 4

W = 71J

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A 0.86 kg rock is projected from the edge of the top of a building with an initial velocity of 8.65 m/s at an angle 46◦ above th
Georgia [21]

Answer:

Height of the building = 11.4 m

Explanation:

As we know that the stone is projected at an angle 46 degree with speed 8.65 m/s

so the two components of the speed is given as

v_x = 8.65 cos46

v_x = 6 m/s

vertical component of the speed is given as

v_y = 8.65 sin46

v_y = 6.22 m/s

now we know that the ball strike at horizontal distance of 13.7 m

so we will have

x = v_x t

13.7 = 6 t

t = 2.28 s

now we know that in vertical direction ball will move under uniform gravity so we can use kinematics

y = v_y t + \frac{1}{2}at^2

y = 6.22(2.28) - \frac{1}{2}(9.81)(2.28^2)

y = -11.4 m

Height of the building = 11.4 m

3 0
3 years ago
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4. What is the opposite reaction pair to gravity?
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What counteracts gravity is buoyancy.
7 0
3 years ago
A truck and a scooter moving with the same velocity colide. Why does the scooter fly off?
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6 0
4 years ago
Given two vectors A--> = 4.20 i^+ 7.20 j^ and B--> = 5.70 i^− 2.40 j^ , find the scalar product of the two vectors A-->
Arisa [49]

Answer:

\vec{A}\times \vec{B}=-51.12\hat{k}

\theta=83.2^{\circ}

Explanation:

We are given that

\vec{A}=4.2\hat{i}+7.2\hat{j}

\vec{B}=5.70\hat{i}-2.40\hat{j}

We have to find the scalar product and the  angle between these two vectors

\vec{A}\times \vec{B}=\begin{vmatrix}i&j&k\\4.2&7.2&0\\5.7&-2.4&0\end{vmatrix}

\vec{A}\times \vec{B}=\hat{k}(-10.08-41.04)=-51.12\hatk}\hat{k}

Angle between two vectors is given by

sin\theta=\frac{\mid a\times b\mid}{\mid a\mid \mi b\mid}

Where \theta in degrees

\mid{\vec{A}}\mid=\sqrt{(4.2)^2+(7.2)^2}=8.3

Using formula\mid a\mid=\sqrt{x^2+y^2}

Where x= Coefficient of unit vector i

y=Coefficient of unit vector j

\mid{\vec{B}}\mid=\sqrt{5.7)^2+(-2.4)^2}=6.2

\mid{\vec{A}\times \vec{B}}\mid=\sqrt{(-51.12)^2}=51.12

Using the formula

sin\theta=\frac{51.12}{8.3\times 6.2}=0.993

\theta=sin^{-1}(0.993)=83.2degrees

Hence, the angle between given two vectors=83.2^{\circ}

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4 years ago
What is the relationship between the force of gravity between two objects in regard to their mass and the distance between them?
Mashcka [7]

Answer:

hi

Explanation:

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3 years ago
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