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NISA [10]
2 years ago
10

How does convection play a role in ocean currents?

Physics
1 answer:
Tom [10]2 years ago
4 0
Convection produces winds and ocean currents. I hope this helped
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Please help me with this question,giving the first correct answer brainliest
elena-s [515]

Answer:

A

Explanation:

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2 years ago
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Bob and John are pulling in different directions. If Bob is pulling to the right with a force of 10N, and John is pulling to the
kykrilka [37]

Answer:

A) -2N

B) Left

C) -0.5

Explanation:

A) -12 + 10

B) More force is acted on in that direction

C) Net force/Mass (-2/4)

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A scientist heats flexible container full of neon gas .what will most likely happen to the container as the gas absorbs heat
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As the container starts to heat up, so will the neon gas. Heat is nothing but energy, and when you add energy to a gas, it will start vibrating much faster and hit the edges of the container at a higher rate and a faster velocity. Therefore, it's possible to deduce that the container will most likely rupture and/or "explode". 
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In the heat equation what does Q represent
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3 years ago
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At noon, ship A is 140 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 25 km/h. How fast (in
Luba_88 [7]

Answer:

The rate of change of distance between the two ships is 18.63 km/h

Explanation:

Given;

distance between the two ships, d = 140 km

speed of ship A = 30 km/h

speed of ship B = 25 km/h

between noon (12 pm) to 4 pm = 4 hours

The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =

140 km - 120 km = 20 km

(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)

The displacement of ship B at 4pm = 25 km/h x 4h = 100 km

Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;

r² = a²   +  b²

r² = 20²  +  100²

r = √10,400

r = 101.98 km

The rate of change of this distance is calculated as;

r² = a²   +  b²

r = 101.98 km, a = 20 km, b = 100 km

2r(\frac{dr}{dt} ) = 2a(\frac{da}{dt} )  + 2b(\frac{db}{dt} )\\\\r(\frac{dr}{dt} ) = a(\frac{da}{dt} )  + b(\frac{db}{dt} )\\\\101.98(\frac{dr}{dt} ) = 20(-30 )  + 100(25 )\\\\101.98(\frac{dr}{dt} ) = -600 + 2,500\\\\101.98(\frac{dr}{dt} ) = 1900\\\\\frac{dr}{dt}  = \frac{1900}{101.98} = 18.63 \ km/h

5 0
3 years ago
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