1000 m/s
100m x 10hz=1000m/s
I’m pretty sure it’s ground but I might be wrong. Sorry
Answer:
y=-1.66 m
Explanation:
We know that
Range R

Here given that
u= 275 m/s
R=75 m
Now by putting the values


θ=0.13°
Now horizontal component of velocity u will be u cosθ.
Horizontal component = 275 cos0.13 = 274.99 m/s
So the time required to cover 180 m in horizontal direction t
180 = 274.99 x t
t=0.65 sec
Now vertical component of velocity u will be u sinθ.
Horizontal component = 275 sin0.13 = 0.62 m/s
So now vertical displacement y will be


y=-1.66 m
Answer:
v = √[ GM / (R + 160934.4 meters) ]
Explanation:
The speed of an object in a circular orbit (in meters per second) is
v = √(GM/r)
where
G = 6.6743e-11 m³ kg⁻¹ sec⁻²
M = the sum of the masses of the planet and the satellite in kilograms
r = the radius of the circular orbit in meters
If the planet's radius, R, is 100 miles, then
v = √[ GM / (R + 160934.4 meters) ]
To solve this problem, we will begin by applying the concept of rotational kinetic energy, defined as the product of half of the Inertia by squared angular velocity. From this relationship we will obtain the value of the angular velocity.

Here,
I = Moment of Inertia
= Angular velocity
Replacing with our values we have that,



Now through the kinematic equations of angular movement we will find the value of the angular acceleration, since this is equivalent to the change of the angular velocity in a certain time, like this:

Replacing,


Finally, Torque's definition tells us that this is equivalent to the product between the moment of inertia and angular acceleration, therefore,



Therefore the torque required is 12.44N-m