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Brut [27]
3 years ago
12

Disturbed by speeding cars outside his workplace, Nobel laureate Arthur Holly Compton designed a speed bump (called the "Holly h

ump") and had it installed. Suppose a 1 800-kg car passes over a hump in a roadway that follows the arc of a circle of radius 18.8 m.
a. If the car travels at 33.0 km/h what force does the road exert on the car as the car passes the highest point of the hump?
b. What is the maximum speed the car can have without losing contact with the road as it passes this highest point?
Physics
1 answer:
Bezzdna [24]3 years ago
3 0
:<span>  </span><span>30.50 km/h = 30.50^3 m / 3600s = 8.47 m/s 

At the top of the circle the centripetal force (mv²/R) comes from the car's weight (mg) 

So, the net downward force from the car (Fn) = (weight - centripetal force) .. and by reaction this is the upward force provided by the road .. 

Fn = mg - mv²/R 
Fn = m(g - v²/R) .. .. 1800kg (9.80 - 8.47²/20.20) .. .. .. ►Fn = 11 247 N (upwards) 
(b) 
When the car's speed is such that all the weight is needed for the centripetal force .. then the net downward force (Fn), and the reaction from the road, becomes zero. 

ie .. mg = mv²/R .. .. v² = Rg .. .. 20.20m x 9.80 = 198.0(m/s)² 

►v = √198 = 14.0 m/s</span>
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Vikentia [17]

Answer:

On average, one acre of new forest can sequester about 2.5 tons of carbon annually. Young trees absorb CO2 at a rate of 13 pounds per tree each year. Trees reach their most productive stage of carbon storage at about 10 years at which point they are estimated to absorb 48 pounds of CO2 per year.

5 0
3 years ago
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a missile is moving 1810 m/s at a 20.0 degree angle. it needs to hit a target 19,500 m away in a 32.0 degree direction in 9.20 s
Ket [755]

Answer:

112 m/s², 79.1°

Explanation:

In the x direction, given:

x₀ = 0 m

x = 19,500 cos 32.0° m

v₀ = 1810 cos 20.0° m/s

t = 9.20 s

Find: a

x = x₀ + v₀ t + ½ at²

19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²

a = 21.01 m/s²

In the y direction, given:

y₀ = 0 m

y = 19,500 sin 32.0° m

v₀ = 1810 sin 20.0° m/s

t = 9.20 s

Find: a

y = y₀ + v₀ t + ½ at²

19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²

a = 109.6 m/s²

The magnitude of the acceleration is:

a² = ax² + ay²

a² = (21.01)² + (109.6)²

a = 112 m/s²

And the direction is:

θ = atan(ay / ax)

θ = atan(109.6 / 21.01)

θ = 79.1°

5 0
2 years ago
If f(x)=4/x+2 and g is the inverse of f,then g'(10)=​
ch4aika [34]

Answer:

g'(10) = \frac{-1}{16}

Explanation:

Since g is the inverse of f ,

We can write

g(f(x)) = x    <em> </em><em>(Identity)</em>

Differentiating both sides of the equation we get,

g'(f(x)).f'(x) = 1

g'(10) = \frac{1}{f'(x)}    --equation[1]    Where f(x) = 10

Now, we have to find x when f(x) = 10

Thus 10 = \frac{4}{x} + 2

\frac{4}{x} = 8

x = \frac{1}{2}

Since f(x) = \frac{4}{x} + 2

f'(x) = -\frac{4}{x^{2} }

f'(\frac{1}{2})  =  -4 × 4 = -16            

Putting it in equation 1, we get:

We get g'(10) = -\frac{1}{16}

5 0
2 years ago
What is the force on a 1025 kg elevator that is falling freely at 9.8 m/sec 2?
kicyunya [14]

Answer:

<h2><u>Given </u><u>:</u><u>-</u></h2>
  • Mass = 1025 kg
  • Acceleration = 9.8 m/s²
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>

Force

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

We know that

F = mg

F = 1025 × 9.8

F = 10,045 N

Or,

10045/1000 = 10.045 Kilo Newton

\\

6 0
3 years ago
What is the average power developed by a motor as it lifts a 400.-kilogram mass at constant speed through a vertical distance of
Tomtit [17]

Answer:

The average power developed by a motor is 4905 Watts.

Explanation:

The average power is given by:

P = \frac{W}{t}

Where:

W: is the work

t: is the time = 8.0 s

First, let's find the work:

W = F*d

Where:

F: is the force

d: is the displacement = 10.0 m

The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

F = mg = 400 kg*9.81 m/s^{2} = 3924 N

Hence, the average power is:

P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W                    

Therefore, the average power developed by a motor is 4905 Watts.

I hope it helps you!                  

3 0
3 years ago
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