Answer:
On average, one acre of new forest can sequester about 2.5 tons of carbon annually. Young trees absorb CO2 at a rate of 13 pounds per tree each year. Trees reach their most productive stage of carbon storage at about 10 years at which point they are estimated to absorb 48 pounds of CO2 per year.
Answer:
112 m/s², 79.1°
Explanation:
In the x direction, given:
x₀ = 0 m
x = 19,500 cos 32.0° m
v₀ = 1810 cos 20.0° m/s
t = 9.20 s
Find: a
x = x₀ + v₀ t + ½ at²
19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²
a = 21.01 m/s²
In the y direction, given:
y₀ = 0 m
y = 19,500 sin 32.0° m
v₀ = 1810 sin 20.0° m/s
t = 9.20 s
Find: a
y = y₀ + v₀ t + ½ at²
19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²
a = 109.6 m/s²
The magnitude of the acceleration is:
a² = ax² + ay²
a² = (21.01)² + (109.6)²
a = 112 m/s²
And the direction is:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ = 79.1°
Answer:
g'(10) = 
Explanation:
Since g is the inverse of f ,
We can write
g(f(x)) = x <em> </em><em>(Identity)</em>
Differentiating both sides of the equation we get,
g'(f(x)).f'(x) = 1
g'(10) =
--equation[1] Where f(x) = 10
Now, we have to find x when f(x) = 10
Thus 10 =
+ 2
= 8
x = 
Since f(x) =
+ 2
f'(x) = -
f'(
) = -4 × 4 = -16
Putting it in equation 1, we get:
We get g'(10) = -
Answer:
<h2><u>Given </u><u>:</u><u>-</u></h2>
- Mass = 1025 kg
- Acceleration = 9.8 m/s²
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>
Force
<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>
We know that
F = mg
F = 1025 × 9.8
F = 10,045 N
Or,
10045/1000 = 10.045 Kilo Newton

Answer:
The average power developed by a motor is 4905 Watts.
Explanation:
The average power is given by:

Where:
W: is the work
t: is the time = 8.0 s
First, let's find the work:

Where:
F: is the force
d: is the displacement = 10.0 m
The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:

Hence, the average power is:
Therefore, the average power developed by a motor is 4905 Watts.
I hope it helps you!