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EastWind [94]
3 years ago
8

What is the formula for sodium bromide

Chemistry
2 answers:
Dominik [7]3 years ago
6 0

Answer:

NaBr

Explanation:

Na is sodium

Br is bromide

jasenka [17]3 years ago
6 0

Answer:

NaBr

Explanation:

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it is a A molecule

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A stock solution has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L. What was the volu
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The volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

<h3>How to calculate volume?</h3>

The concentration of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

  • C1 = initial concentration = 1.5M
  • C2 = final concentration = 0.54M
  • V1 = initial volume = ?
  • V2 = final volume = 0.18L

1.5 × V1 = 0.54 × 0.18

1.5V1 = 0.0972

V1 = 0.0972 ÷ 1.5

V1 = 0.065L

Therefore, the volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

Learn more about volume at: brainly.com/question/1578538

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Which of the following is a cause of a dna mutation
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4). One mole of monoclinic sulfur at 25C was placed in a constant-pressure calorimeter whose heat capacity (C) was 1620 J/K. T
andre [41]

<u>Answer:</u> The enthalpy change of the reaction is -243 J/mol

<u>Explanation:</u>

The heat released by the reaction is absorbed by the calorimeter and the solution.

The chemical equation used to calculate the heat released follows:

q=c\times \Delta T

where,

c = heat capacity of calorimeter = 1620 J/K

\Delta T = change in temperature = 0.150^oC=0.150K   (Change remains same)

Putting values in above equation, we get:

q=1620J/K\times 0.15K=243J

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

For the given chemical reaction:

S\text{ (monoclinic)}\rightarrow S\text{ (orthorhombic)}

We are given:

Moles of monoclinic sulfur = 1 mole

  • To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,  

q = amount of heat released = -243 J

n = number of moles = 1 mole

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-243J}{1mol}=-243J/mol

Hence, the enthalpy change of the reaction is -243 J/mol

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