Answer:
The correct option is;
S is more nucleophiclic than O because S is larger than O therefore S is less well solvated than O
Explanation:
Here we have
As the size of atoms increases, the basicity increases and the nucleophilicity increases. Therefore since S is larger than O it is more nucleophilic than O.
Also we have smaller nucleophiles are more solvated than larger nucleophiles therefore S is less well solvated than O.
Which gives the correct answer as;
S is more nucleophiclic than O because S is larger than O therefore S is less well solvated than O.
The electrons are transferred from potassium to sulphur, in this reaction, potassium is being oxidised and sulphur is being reduced. Two potassium atoms each lose one electron forming K+ ions. Sulphur gains two electrons forming S2-/2- ions. The resultant formula will be: K2S, bonding in this compound is ionic.
A pi bond... hope this helps!!!!!
double-displacement reaction
Explanation:
We have the chemical reaction:
Na₂S (aq) + Cd(NO₃)₂ (aq) → CdS (s) + 2 NaNO₃ (aq)
where:
(aq) - aqueous
(s) - solid
This is a double-displacement reaction because the reactants exchange atoms or group of atoms between themselves to form the products. To drive the reaction to the right, one of the products is a precipitate.
Generally we can express the double-displacement reaction as following:
AB + CD → AC + BD
Learn more about:
types of chemical reactions
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