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3 years ago

If you exert a force on an object in motion you will change its ____.

2 answers:

4 0

If you exert a force on an object in motion, then depending on the
direction of the force you exert and the direction in which it's already
moving, you may speed it up, slow it down, or change the direction
of its motion. Any of these changes is called an acceleration.

In addition to that, you'll change the object's momentum and kinetic energy.
They may increase or decrease ... again depending on the directions of the
motion and the new force.

You will not change the object's mass, inertia, weight, color, cost,
political affiliation, or gender preference.

Pachacha [2.7K]3 years ago

4 0

It would be D.
momentum

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If the relative humidity is 25 nd the saturation mixing ratio is 24g/kg, what is the mixing ratio?

levacccp [35]

The mixing ratio is 6.

To find the answer, we have to know about the mixing ratio.

<h3>What is mixing ratio?</h3>

The mixing ratio must be calculated in a complex manner.
A saturated vapor pressure (es) for values of air temperature and an actual vapor pressure (e) for values of dewpoint temperature must be determined in order to determine the mixing ratio.
The air temperature and/or dewpoint temperature must first be converted to degrees Celsius (°C) before the vapor pressures can be calculated.
The equation below can be used to determine the relative humidity (rh), as well as the actual mixing ratio and saturated mixing ratio,

$Rh=\frac{w}{w_s} *100$

where; w is the mixing ratio and w(s) is the saturation mixing ratio.

In our question, it is given that,

$Rh=25\\w_s=24$

Thus, the mixing ratio will be,

$w=\frac{Rh*w_s}{100} =\frac{25*24}{100}=6$

Thus, we can conclude that, the mixing ratio is 6.

Learn more about mixing ratio here:

brainly.com/question/8791831

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JulijaS [17]

Answer:

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2 years ago

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3 years ago

Read 2 more answers

When the play button is pressed, a CD accelerates uniformly from rest to 450 rev/min in 3.0 revolutions. If the CD has a radius

Marina CMI [18]

To solve this problem it is necessary to apply the kinematic equations of angular motion.

Torque from the rotational movement is defined as

$\tau = I\alpha$

where

I = Moment of inertia $\rightarrow \frac{1}{2}mr^2$ For a disk

$\alpha =$ Angular acceleration

The angular acceleration at the same time can be defined as function of angular velocity and angular displacement (Without considering time) through the expression:

$2 \alpha \theta = \omega_f^2-\omega_i^2$

Where

$\omega_{f,i} =$ Final and Initial Angular velocity

$\alpha =$ Angular acceleration

$\theta =$ Angular displacement

Our values are given as

$\omega_i = 0 rad/s$

$\omega_f = 450rev/min (\frac{1min}{60s})(\frac{2\pi rad}{1rev})$

$\omega_f = 47.12rad/s$

$\theta = 3 rev (\frac{2\pi rad}{1rev}) \rightarrow 6\pi rad$

$r = 7cm = 7*10^{-2}m$

$m = 17g = 17*10^{-3}kg$

Using the expression of angular acceleration we can find the to then find the torque, that is,

$2\alpha\theta=\omega_f^2-\omega_i^2$

$\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}$

$\alpha = \frac{47.12^2-0^2}{2*6\pi}$

$\alpha = 58.89rad/s^2$

With the expression of the acceleration found it is now necessary to replace it on the torque equation and the respective moment of inertia for the disk, so

$\tau = I\alpha$

$\tau = (\frac{1}{2}mr^2)\alpha$