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2 years ago

A solid cylinder with diameter 20cm has an angular velocity of 10m/s and angular momentum of 2kgm^2/s. What is its mass?

Physics

1 answer:

Sati [7]2 years ago

4 0

Hi there!

Recall the equation for angular momentum:
$L = I\omega$

L = Angular momentum (kgm²/s)
I = Moment of Inertia (kgm²)
ω = angular velocity (rad/s)

We know that the Moment of Inertia of a solid cylinder is equivalent to:
$I = \frac{1}{2}MR^2$

M = mass (kg)
R = radius (m)

Plug in the givens to solve for the moment of inertia. Remember to divide the diameter by 2 for the radius, and to convert to meters.

$r = \frac{d}{2} = 20/2 = 10 cm \\\\10 cm = 0.1 m$

$I = \frac{1}{2}M(0.1^2) = 0.005 M$

We can rearrange the equation of angular momentum to solve for mass.

$L = 0.005M * \omega\\\\\frac{L}{0.005 \omega} = M \\\\M = \frac{2}{0.005(10)} = \boxed{ 40 kg}$

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2 years ago

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3 years ago

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Answer:

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Hence, the ground speed of the plane is 96.68 km/h.

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3 years ago