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AVprozaik [17]
3 years ago
13

Which option is a balanced equation for cellular respiration?

Chemistry
2 answers:
qwelly [4]3 years ago
8 0
The first one, but should be:
C6H12O6 + 6O2 -> 6CO2 + 6 H2O
Alex73 [517]3 years ago
6 0

Answer: the answer is 6CO2 + 6H2O C6H12O6 + 6O2

Explanation: I just finished the quiz

!HOPE IT HELPS!

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Which statement is true about a liquid but not a gas?
vovangra [49]

Answer:

I think its D

Explanation:

.........................

3 0
3 years ago
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. Give an example of a salt that is less soluble when the temperature increases
77julia77 [94]

Answer:

cerium (iii) sulfate is less soluble

6 0
3 years ago
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There is a gas pressure in a container that is 123kPa what is the pressure in atmospheres ?
Vera_Pavlovna [14]

Answer:

In strict SI units (highly recommended), express n in moles, R is the universal gas constant R=8.314Jmol−K , T is the temperature in Kelvins, and the volume V is in m3 . The resulting pressure P will be in Pa. R=0.082054L−atmmol−K , in which case the pressure is calculated in atm.

8 0
3 years ago
What mass of propane could burn in 48.0 g of oxygen? C3H8 + 5O2 → 3CO2 + 4H2O
Ipatiy [6.2K]

Answer:

Mass = 13.23 g  

Explanation:

Given data:

Mass of oxygen = 48.0 g

Mass of propane burn = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂     →      3CO₂ + 4H₂O

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 48.0 g/ 32 g/mol

Number of moles = 1.5 mol

now we will compare the moles of propane and oxygen.

              O₂           :          C₃H₈

               5            :            1

             1.5            :          1/5×1.5 = 0.3 mol

Mass of propane burn:

Mass = number of moles × molar mass

Mass = 0.3 mol × 44.1 g/mol

Mass = 13.23 g  

6 0
3 years ago
A gas occupies a volume of 40.0 milliliters at 20 c if the volume is increased too 80.0 milliliters at constant pressure, the re
Troyanec [42]
Charles law gives the relationship between temperature and volume of gases. It  states that the volume of gas is directly proportional to temperature at constant pressure. 
V / T = k 
where V - volume and T - temperature in Kelvin and k - constant 
\frac{V1}{T1} =  \frac{V2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - 20 °C + 273 = 293 K
substituting these values in the equation 
\frac{40.0 mL}{293 K}  =  \frac{80.0 mL}{T}
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C
8 0
3 years ago
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