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3 years ago

Which option is a balanced equation for cellular respiration?

Chemistry

2 answers:

qwelly [4]3 years ago

8 0

The first one, but should be:
C6H12O6 + 6O2 -> 6CO2 + 6 H2O

Alex73 [517]3 years ago

6 0

Answer: the answer is 6CO2 + 6H2O C6H12O6 + 6O2

Explanation: I just finished the quiz

!HOPE IT HELPS!

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Use your experimentally determined value of ksp and show,by calculations, that ag2cro4 should precipitate when 5ml of 0.004m agn

Doss [256]

When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)

So, according to the balanced equation of the reaction:

and by using ICE table:

Ag2CrO4(s) → 2Ag+ (Aq) + CrO4^2-(aq)

initial 0 0

change +2X +X

Equ 2X X

∴ Ksp = [Ag+]^2[CrO42-]

so by substitution:

∴ 3.83 x 10^-11 = (2X)^2* X

3.83 x 10^-11 = 4 X^3

∴X = 2.1 x 10^-4

∴[CrO42-] = X = 2.1 x 10^-4 M

[Ag+] = 2X = 2 * (2.1 x 10^-4)

= 4.2 x 10^-4 M

when we comparing with the actual concentration of [Ag+] and [CrO42-]

when moles Ag+ = molarity * volume

= 0.004 m * 0.005L

= 2 x 10^-5 moles
[Ag+] = moles / total volume

= 2 x 10^-5 / 0.01L

= 0.002 M

moles CrO42- = molarity * volume

= 0.0024 m * 0.005 L

= 1.2 x 10^-5 mol

∴[CrO42-] = moles / total volume

= (1.2 x 10^-5)mol / 0.01 L

= 0.0012 M

by comparing this values with the max concentration that is saturation in the solution

and when the 2 values of ions concentration are >>> than the max values o the concentrations that are will be saturated.

∴ the excess will precipitate out

8 0

2 years ago

In general, ionization energy will

IRISSAK [1]

Answer:

Explanation:

The correct answer is A.

5 0

3 years ago

Read 2 more answers

What is the molality, m, of an aqueous solution of ammonia that is 12.83 M NH3 (17.03 g/mol)? This solution has a density of 0.9

daser333 [38]

Answer:

Molality = 18.5 m

Explanation:

Let's analyse data. We want to determine molality which means mol of solute / 1kg of solvent. (Hence we need, the moles of solute and the mass of solvent in kg)

12.83 M means molarity → mol of solute in 1L of solution

Density refers always to solution → Mass of solution / Volume of solution

1L = 1000 mL

We can determine the mass of solution with density

0.9102 g/mL = Mass of solution / 1000 mL

Mass of solution = 0.9102 g/mL . 1000 mL → 910.2 g

Let's convert the moles of solute (NH₃) to mass

12.83 mol . 17.03 g/ 1 mol = 218.5 g

We can apply this knowledge:

Mass of solution = Mass of solvent + Mass of solute

910.2 g = Mass of solvent + 218.5 g

910.2 g - 218.5 g = 691.7 g → Mass of solvent.

Let's convert the mass in g to kg

691.7 g . 1kg / 1000 g = 0.6917kg

We can determine molalilty now → 12.83 mol / 0.6917kg

Molality = 18.5 m

6 0

3 years ago

recommend an element use to fill bottles that contain ancient paper. the element should be a gas at room temperature, should be

Eduardwww [97]

Okay so we are given these requirements:

element which can be used to stuff bottles that enclose ancient paper
must be a gas at room temperature
must be denser than helium
must not react with other elements

The only element that comes into my mind is:

<span>Argon</span>

6 0

3 years ago

Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the n

kipiarov [429]

Answer:

The length of an edge of this unit cell is 407.294 pm

Explanation:

Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.

To determine the edge length, a relationship between the radius of the atom and edge length is used.

X = R√8

Where;

X is the length of an edge of this unit cell

R is the radius of the gold atom = 144 pm = 144 X 10⁻¹² m

X = 144 X 10⁻¹²√8

X = 407.294 X 10⁻¹² m

X = 407.294 pm

Therefore, the length of an edge of this unit cell is 407.294 pm

8 0

2 years ago