Explanation:
where,
R = Gas constant =
T = temperature =
= equilibrium constant at 600°C = 0.900
Putting values in above equation, we get:
The ΔG° of the reaction at 764.85 J/mol is 764.85 J/mol.
Equilibrium constant at 600°C =
Equilibrium constant at 1000°C =
The ΔH° of the reaction at 600 C is -18,969.30 J/mol.
ΔG° = ΔH° - TΔS°
764.85 J/mol = -18,969.30 J/mol - 873.15 K × ΔS°
ΔS° = -22.60 J/K mol
The ΔS° of the reaction at 600 C is -22.60 J/K mol.
Partial pressure of carbon dioxide =
Partial pressure of carbon monoxide =
Where mole fraction of carbon dioxide and carbon monoxide gas.
The expression of is given by:
Mole fraction of carbon dioxide at 600°C is 0.474.
C because it’s increasing not decreasing
Did you mean the atomic mass?
Starting in 1908, while a professor at the University of Chicago, Millikan worked on an oil-drop experiment in which he measured the charge on a single electron. J. J. Thomson had already discovered the charge-to-mass ratio of the electron.
Answer:
for instance :
water , H²O , and hydrogen peroxide . H²O² , are alike
in that their respective molecules are composed of hydrogen and oxygen atomd . hope its helpful . Good luck :)