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Nookie1986 [14]
3 years ago
5

Suppose an electron and a proton move at the same speed. which particle has a longer de broglie wavelength? suppose an electron

and a proton move at the same speed. which particle has a longer de broglie wavelength? the proton has the longer de broglie wavelength. since both are particles, it is meaningless to discuss a wavelength associated with them. both have the same de broglie wavelength. the electron has the longer de broglie wavelength.
Physics
1 answer:
BARSIC [14]3 years ago
6 0
When both particles, the electron and the proton move at the same speed, they may have differences with their de Broglie wavelength, the particle that would have a longer wavelength would be the proton since the wavelength is in direct proportionality with the mass of the particle.
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E. Galaxy Cluster

Explanation:

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A megaparsec is a million parsecs and there are about 3.3 light years in a mega-parsec. Parsec is rather a natural distance unit for astronomers. The standard abbreviation of a mega-parsec is Mpc.

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A circuit with resistive elements of 220, 100, 57, and 43 produce what total resistance?
Korvikt [17]

The total resistance is 420 ohm.

A circuit with resistive elements of 220, 100, 57, and 43 produce what total resistance  

 R= 220+ 100+ 57+ 43

    = 420 Ω

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8 0
2 years ago
A particular balloon can be stretched to a maximum surface area of 1257 cm2. The balloon is filled with 3.1 L of helium gas at a
chubhunter [2.5K]

Answer:

The ballon will brust at

<em>Pmax = 518 Torr ≈ 0.687 Atm </em>

<em />

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Explanation:

Hello!

To solve this problem we are going to use the ideal gass law

PV = nRT

Where n (number of moles) and R are constants (in the present case)

Therefore, we can relate to thermodynamic states with their respective pressure, volume and temperature.

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} --- (*)

Our initial state is:

P1 = 754 torr

V1 = 3.1 L

T1 = 294 K

If we consider the final state at which the ballon will explode, then:

P2 = Pmax

V2 = Vmax

T2 = 273 K

We also know that the maximum surface area is: 1257 cm^2

If we consider a spherical ballon, we can obtain the maximum radius:

R_{max} = \sqrt{\frac{A_{max}}{4 \pi}}

Rmax = 10.001 cm

Therefore, the max volume will be:

V_{max} = \frac{4}{3} \pi R_{max}^3

Vmax = 4 190.05 cm^3 = 4.19 L

Now, from (*)

P_{max} = P_1 \frac{V_1T_2}{V_2T_1}

Therefore:

Pmax= P1 * (0.687)

That is:

Pmax = 518 Torr

6 0
3 years ago
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