Answer:
<u><em>Definition of spectral line: </em></u><em>one of a series of linear images formed by a spectrograph or similar instrument and corresponding to a narrow portion of the spectrum of the radiation emitted or absorbed by a particular source.</em>
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<u><em>Definition of Wavelength:</em></u><em> can be defined as the distance between two successive crests or troughs of a wave. It is measured in the direction of the wave. ... Wavelength is inversely proportional to frequency. This means the longer the wavelength, lower the frequency.</em>
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<em>So, the spectrum is the range of wavelength in visible light. While, wavelength is the length of a wave.</em>
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Explanation:
I hope this helps!
Storing music digitally requires less storage room than analog records or tapes. Digital music is easier to copy and the copies are the same as the original. The quality of the signal does not degrade over long periods of time.
Each person is 80kg. 320/4
A circuit which only has one path for current to follow
Answer:
- magnitude : 1635.43 m
- Angle: 130°28'20'' north of east
Explanation:
First, we will find the Cartesian Representation of the
and
vectors. We can do this, using the formula

where
its the magnitude of the vector and θ the angle. For
we have:


where the unit vector
points east, and
points north. Now, the
will be:

Now, taking the sum:

This is




Now, for the magnitude, we just have to take its length:



For its angle, as the vector lays in the second quadrant, we can use:



