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aivan3 [116]
3 years ago
13

Someone help me solve this please and explain

Physics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

i think you minus The weights I think

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. A 1.00 kg rock is thrown up into the air from ground level at a speed of 8.00 m/s. The ball travels up
Liula [17]

Answer:

p = -8 kg-m/s

Explanation:

Given that,

Initial speed of the rock, u = 8 m/s

Mass of the rock, m = 1 kg

The ball travels up  to a maximum height, then returns to the ground.

We need to find the rock's momentum as it strikes the  ground. Let v be the final speed of the rock. Its final speed is as same as initial speed i.e. 8 m/s but in negative direction. So

p = mv

p = 1 kg × (-8 m/s)

= -8 kg-m/s

So, the rock's momentum as it strikes the  ground is (-8 kg-m/s).

5 0
3 years ago
The speed limit sign in indiana reads 60 miles per hour. convert these units to meters per second
cluponka [151]

Answer:

26.822 m/s

Explanation:

60 mi/hr  *  5280 ft/mile *  1 hr / 3600 sec  *  12 in / foot * 1 meter / 39.37 in = <u>26.822 m/s</u>

3 0
2 years ago
With what force will a car hit a tree if the car has a mass of 3,000 kg and it is accelerating at a rate of 2m/s2
Arisa [49]
<span>F=ma = 3000x2m/sec^2 =6000 newtons. </span>
6 0
3 years ago
Learning Goal: To understand the behavior ofthe electric field at the surface of a conductor, and itsrelationship to surface cha
Ivan

Complete Question

The complete question is shown on the first uploaded image  

Answer:

a   it is always zero

b  0

c  \eta  =  -\epsilon _o E

Explanation:ss

Here the  net charge is  on the outer surface of the conductor thus this means that the net charge inside the conductor is zero

Generally the charge density of a conductor is dependent on the charge per unit area  which implies that the charge density is dependent on the net charge  so this  means that the charge density inside the conductor is zero

 

Generally the direction of electric field this from the  positive charge to the negative charge  so from the question we can deduce  that the negative charge is located on the surface of the conductor

    So We can mathematically define the charge density on the surface of the electric field as

             ∮E \cdot dA =  \frac{-Q}{\epsilon _o}

Where E is the electric field

          dA change in unit area

           -Q is the negative charge

          \epsilon _o  is the permittivity of free space

So

          EA  =  \frac{-Q}{\epsilon _o }

           \frac{Q}{A}  =  -\epsilon _o E

          \eta  =  -\epsilon _o E

Where \eta is the charge density

   

8 0
3 years ago
When an experiment is replicated, how should the results of the two experiments compare?
olasank [31]
When the experiment is replicated, this means the conduction of the second experiment, should be related, or similar, to your first results. 
4 0
3 years ago
Read 2 more answers
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