3 years ago

Someone help me solve this please and explain

Physics

1 answer:

vfiekz [6]3 years ago

8 0

Answer:

i think you minus The weights I think

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At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

Ymorist [56]

Answer:440.03 N

Explanation:

Given

horizontal component of acceleration $(a_x)=800 m/s^2$

vertical component of acceleration $(a_y)=880 m/s^2$

mass of ball =0.37 kg

Force in horizontal direction $=m\times a_x=0.37\times 800=296 N$

Force in vertical direction $=m\times a_y=0.37\times 880=325.6 N$

Therefore net force is

$F=F_x+F_y$

$|F|=\sqrt{296^2+325.6^2}$

|F|=440.03 N

5 0

3 years ago

saad has mass 80kg when resting on the ground at the equator what will be the centripetal acceleration on saad if the radius of

Sidana [21]

Thank you for posting your question here at brainly. Below is the answer:

m = 80 kg
R = 6.4 x 10^6 m
Earth completes one rotation in 24 hours
Thus, T = 24 x 3600 s
Centripetral acceleration is given by
ac = w^2R
ac = (2 pie/T)^2R
ac = (2 pie/T)^2R = 4 pie^2/(24 x 3600)^2 x 6.4 x 10^6
ac = 0.034 m/s^2

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3 years ago

If a proton were released from rest at the sphere's surface, what would be its speed far from the sphere?

balu736 [363]

Let the sphere is having charge Q and radius R

Now if the proton is released from rest

By energy conservation we can say

$U = K$