What does the "129" represent in the following notation? *
Te-129
Hey there!
Molar mass CuSO4 = <span>159.609 g/mol
</span><span>Note that the molarity is in the enunciation of the issue, then the problem asks the mass of the solute :
Volume in liters of solution:
150 mL / 1000 => 0.15 L
</span><span>Calculation of quantity in Moles of the solute :
</span>
1 L ----------------- 0.300 M
0.15 L ------------ ( moles )
Moles CuSO4 = 0.15 * 0.300 / 1
Moles CuSO4 = 0.045 moles
Therefore :
1 mole CuSO4 --------------------- 159.609 g
0.045 moles CuSO4-------------- mass
mass = 0.045 * 159.609 / 1
mass = 7.182405 g of CuSO4
Answer:
See explanation
Explanation:
The slope of a graph in which mass was plotted against volume is the density of the object. Density of objects have been measured and recorded in standard handbooks for the purpose of reference. If the density of an unknown substance is measured, it can now be compared with the density of known substances recorded in standard handbooks such as the handbook of physics and chemistry. By so doing, the unknown substance can be identified.
According to standard handbooks, the density of copper is 8.96 g/ml while that of nickel is 8.908 g/ml. If the average slope obtained is around 8.96 g/ml, then the metal is copper and not nickel.
An alternative to this method is to measure the refractive index of the piece of metal and compare the average values observed with the contents of standard handbooks in order to identify the unknown metal.
<span>Answer: yes, when you balance a chemical reaction, you are making sure that the law of conservation of matter is obeyed.
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Justification:
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<span>1) When you balance a chemical reaction, you add the coefficients to make the number of atoms of each element in the left side of the equation (reactants) equal to number of atoms of the same elements in the right side (products).
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<span>2) Since, each atom has a unique atomic mass associated, it results, necessarily, that the mass of the atoms of the reactants is equal to the mass of the atoms of the products</span>.